World vision australia Interview Questions, Process, and Tips

6 cuts

That will depend heavily on when in the journey the 200 men join.

3000(4x/100) + 5000(2x/100)=10

5

6 yeara old

8 days

5 (3+2)
if he wins then it becomes 4 double than 2
and if looses then opponent becomes 3 which is equal.

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

X-Y=-1

(C*D)/G

Let the total number of matches to played in the tournament be ‘x’.

Given that A county cricket team has won 10 matches and lost 4.

That means total number of matches played = 14.

So,

= > 70% of x = 14

= > (70/100) * x = 14

= > 70x = 1400

= > x = 20.

So, the number of matches to be played = 20.

They have a record of exactly 75% wins = 20 * 75/100

= > 15.

Therefore, the number of matches should the team win = 15 – 10 = 5.

Hope this helps!

Answer: 40

Explanation:
800*(25/100) = 200 —- 5

? —- 1 => Rs.40

total sum = 205 Rs.

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​