Sincro logistica Interview Questions, Process, and Tips

speed=mile/hour
.•. time taken to travel M miles is

So, time =distance/speed
=M/m/h
=Mh/m hrs

Let the age of the man be x
Then age of his son becomes (x−24)

2 years later from now,

Age of man will be = x+2
and age of his son will be =(x−24+2)=x−22

According to question,

2(x−22)=x+2

i.e., 2x−44=x+2

i.e., x=46

Therefore ,
Present age of man=46 years
And present age of his son =46−24=22 years

Sachin is 14 years old whereas Rahu is 18 years old.

we know,
area=b*h
b gets increased by 20% i.e (b+0.20b)
h gets decreased by 20% i.e (h-0.20h)
rewriting the equation(area=b*h),
area=(b+0.20b)*(h-0.20h)
area=b(1+0.20)*h(1-0.20)
area=b(1.20)*h(0.80)
area=b*h*(1.20)*(0.80)
area=b*h*(0.96)
i.e new area=0.96 times the original area
if 100% was the original area,it has decreased to 96%
so,100%-96%= 4%

let x be lenghth of candles.

thicker one—- in 1 hr 1/6th will go.
thinner one— in 1 hr 1/4th will go.

let he lit for n hrs.

so in n hrs thicker one goes n/6.
and thinner one goes n/4.

so remainini length are x-n/6 and x-n/4.so x-n/6=2(x-n/4)
implie n=3x. if x=1 n=3hrs.

24kmph

time taken = x/40 + 2x/20
=> x=8
so, 3x = 24

17:3

Friends,
The Answer given by ‘Gaurav Sharma’ is correct and
the approach (bottom to top) suggested by ‘Shailesh’ is
good. But with minor correction we can arrive the solution
using this approach:
After 5th loot, No. of breads left = 3
after 4th loot, no. of breads left = (3+0.5)x2 = 7
after 3rd loot, no. of breads left = (7+0.5)x2 = 15
after 2nd loot, no. of breads left = (15+0.5)x2 = 31
after 1st loot, no. of breads left = (31+0.5)x2 = 63
So, before 1st loot, no. of breads left = (63+0.5)x2 = 127

189

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