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Ques:- A person meets a train at a railway station coming daily at a particular time. One day he is late by 25 minutes, and he meets the train 5 k.m. before the station. If his speed is 12 kmph, what is the speed of the train.
Recent Answer : Added by DK BOSS On 2021-07-30 16:27:20:
Ans: 60 kph
Suppose Person meets the train everyday at 3 PM at Station A.
His speed is 12kph.
So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.
But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.
Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.
So speed of the train is 5KM/5min = 60 kph.
Ques:- 49 race cars and no two have the same speed. Now give you 7 tracks with equal length to find the 25th fastest car. At least how many races are needed.(no time recorder)
Ques:- Which is better to grow plants in Rock sand or soil?
Ques:- What things give you greatest satisfaction?
Ques:- Why you want to chose this compeny
Ques:- Greengrocer C. Carrot wants to expose his oranges neatly for sale. Doing this he discovers that one orange is left over when he places them in groups of three. The same happens if he tries to place them in groups of 5, 7, or 9 oranges. Only when he makes groups of 11 oranges, it fits exactly. How many oranges does the greengrocer have at least?
Recent Answer : Added by Mohamed Raja M On 2022-04-02 07:00:18:
transistor is a semiconductor device for amplifying ,controlling and generating the electrical signals.
Ques:- A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?
Recent Answer : Added by Anonymous On 2021-08-14 13:06:13:
Let:
1. speed of boat in still water = x
2. speed of stream = y;
Then net speed of boat upstream = x – y = 16km / 4 h = 4kmph
Net speed of boat downstream = x + y = 16 / 2 = 8kmph
Now solve for x to get x = 6kmph in still water.
Ques:- X and Y start a business jointly. X invests Rs.16000 for 8 months and Y remains in the business for 4 months. Out of the total profit Y claims 2/7th share. How much money is contributed by Y?
Recent Answer : Added by Admin On 2022-09-29 18:33:42:
Ques:- Rs.590 is divided amongst A, B, C so that 5 times A’s share, six times B’s share and eight times C’s share are all equal. Find C’s share?
Recent Answer : Added by Swati On 2021-01-05 15:58:25:
C=150
Ques:- In a round table conference six persons are participating, They are Andy, Bob, Charles, Douglas, Elena and Fred. Bob is sitting between Charles and Elena and is opposite to Andy. Douglas is sitting to the left of Elena. Who is sitting opposite to Douglas?
Recent Answer : Added by DK BOSS On 2021-07-16 09:53:12:
Answer: Option D
Explanation:
As Bob is sitting between Charles and Elena and Douglas is sitting to the left of Elena. We get the following arrangement.
Andy is opposite Bob. Therefore, the final arrangement is as follows.
Fred will be sitting right of Charles if each person interchange his/her place with the person sitting opposite them.
Ques:- A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
Ques:- A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 60 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?
Recent Answer : Added by Cynthia Birungi Muhumuza On 2022-08-14 16:34:47:
60 more men
Ques:- Tell me the one thing that you like about our company?
Ques:- Can you talk about a person who inspires you and why?
Ques:- What are your future goals? Tell me about your short term and long-term goals.
Ques:- Give an example of a time you had to respond to an unhappy manager/ customer/ colleague/ professor/ friend.
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Ans: 60 kph
Suppose Person meets the train everyday at 3 PM at Station A.
His speed is 12kph.
So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.
But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.
Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.
So speed of the train is 5KM/5min = 60 kph.