Flink Interview Questions, Process, and Tips

6

24kmph

time taken = x/40 + 2x/20
=> x=8
so, 3x = 24

It is assumed to be constant. Now, to cross past the pole, the train should cover a distance of x meters. Now, the time taken by the train to cross a platform of length 100 m is 25 seconds. Hence, the length of the train is 150 m.

37 SEATS….
because if passengers will occupy 3 seats, per head amount
payable will be 26.89.80.67 can not be divisible other than
3 and 26.89. so the,
Number of occupied seats will be 3
Number of unoccupied seats will be 40-3=37

Divide 30*60 seconds by LCM of Numbers =15

Use 3pt. Formula
( (x-x1)/(x2-x1) )=( (y-y1)/(y2-y1) )
We get 150

take goat from one side and leave it another side and then come back another side and carry cabbage from one side leave it near goat and carry goat back to other side and then carry wolf leave it another side with cabbage come back to
goat side and carray goat to other side not all three are there on another side

127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)

100

995

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