Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Ques:- Who is the chief justice of supreme court?
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Recent Answer : :
50
Ques:- X, Y and Z can do a work in 6, 8 and 12 days respectively doing the work together and get a payment of Rs.1800. What is Y’s share?
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Ques:- Can you explain why should we select you fromthe number of applications we have received?
Ques:- In a grass field, If there are 40 cows, they could eat for 40 days. If there are 30 cows, they could eat for 60 days. Than if 20 cows, How much day they could eat?
A. 60
B. 80
C. 55
D. 50
Recent Answer : :
40
40
30
60
– 10 cows
+ 20 days
if 40 cows can eat for forty days
then 20 cows can eat for 80 days
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Ques:- The difference between the local value and the face value of 7 in the numeral 32675149 is
A. 5149
B. 64851
C. 69993
D. 75142
Recent Answer : :
The local value of 7 in the number is at 10000 so 7×10000 and face of 7 is 7
So 70000 -7 so the answer is C 69993
Ques:- Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
Recent Answer : :
1/x=1/5+1/10+1/30=lcm is 30.
->30/5=6
->30/10=3
->30/30=1
1/x=6+3+1=10
1/x=10/30=1/3=x=3
Ans is 3 hr.
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Ques:- Find out the wrong number in the series:
1, 3, 10, 21, 64, 129, 356, 777
1, 3, 10, 21, 64, 129, 356, 777
A. 356
B. 129
C. 64
D. 10
Recent Answer : :
a
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A. Basketball
B. Hockey
C. Golf
D. None of these
Recent Answer : :
Hockey
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Recent Answer : :
I will deny
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Ques:- Which is the largest?
A. (125)^15
B. (5)^125
C. (625)^20
D. (25)^10
Recent Answer : :
125^15 would be 5^18
625^20 would be 5^24
25^10 would yield 5^12
so
The answer is b) i.e. 5^125
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Recent Answer : :
When I went to my native place the form is so good environment
Ques:- Tell me abot your self
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds