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The answer is A)

y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg

y2 – y1 = 10 Rs/kg

The distance between the y and y1 is

y – y1 = 64.5 – 62 = 2.5

x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75

The target price is calculated by the lever method.

x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5

The ratio is of y1 to y2 is

0.75 : 0.25

Divide by both by 0.25

3 : 1

-1

5 litre jug contains 4 litres of salt water solution
with 15% of salt, that means it has 4000*.15 = 600 ml salt
in it.
If 1.5 litres solution is spills out, remaining solution
is 2.5 litres, then the salf content is 2500*.15 = 375ml.
Now, the jug is filled to full capacity with water i.e.,
now the jug has 5 litre solution in it.
Now, the salt content is 375/5000 = 7.5%

Violet

1^1,2^2,3^3,4:^4,5^5,6^6
1,4,27,256,3125,46656

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