The sultan center Interview Questions, Process, and Tips

( d ) 6 days

When I went to my native place the form is so good environment

500 = Total+50
Total(450) = only one paper(p) + 29+20+35 + all three (g)
285+212+127 = p + 2( 29+20+35 )+ 3g
solve above .. to get g = 45 …
( small corrctn .. i think .. questn shud be 20 read ONLY
hindu and
times of India and 29 read ONLY hindu and Indian express
and 35
read ONLY times of India and Indian express)

X share is 10500
Y share is 13500
Z share is 16500

say the work is w and let no of days taken by b is ‘x’ which
we have to calculate
so work done by a in one day is w/6
work done by b in one day is w/x
a and b together can do work in 4 days ie=(w/6)+(w/x)=(w/4)
solving equation x=12
so no of days taken by b=12

(x+2)^2 -x^2 = 84
X=20
So (20,22)
Sum= 42

North-east

pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144×100)/60
X=240
total students=240

Lets call the 5 litre jug as jug A and 3 litre jug as jug B. Now, follow the steps:

Fill jug A completely. Now it contains 5 litres.
Slowly pour the water from jug A to jug B until jug B is completely filled. Now, jug A contains 2 litres and jug B contains 3 litres.
Throw away the water in jug B so that it is completely empty. Now, jug A contains 2 litres and jug B is empty.
Transfer the water from jug A to jug B. Now, jug A is empty and jug B contains 2 litres.
Fill jug A completely. Now, jug A contains 5 litres and jug B contains 2 litres.
Transfer water from jug A to jug B until jug B is completely filled. Now, jug A contains 4 litres and jug B contains 3 litres.

Now you have 4 litres of water in jug A.

let the speed limit be x.
speed by first rider S1 and 2nd rider be S2.
S1=x+10;
ans S2=x+2*10; and given S2=35.
solving we get x=15mph.

$20

10000

one-legged =5% of 10000=500

remaining=10000-500=9500

barefooted=9500/2=4750

remaining people= 9500-4750=4750

hence required number of shoes= 4750*2+500*1=100005% of 10000 = 500 one legged

9500 / 2 = 4750 bare foot

minium no of shoes = 4750*2 + 500*1 = 10000

Answer: C

Explanation:

900 — 100
100 — ? => 100/900*100 => 11.11%