these are question tht are seem to be like it consumes
time. so dont see jus the question and run to the next .
ans. a) 12
if 9 balls are added then the ratio to the combination
becomes 2:4:3.
9 balls make the ratio 3 for grey balls in tht mixture.
so the factor is 9/3 = 3 (in tht mixture)
so the same factor has to be maintained through out the
ratio. so black balls is 4 * 3 = 12 and white balls is 2 *
3 = 6.
ans is C.
let H be present age of husaband.W be present age of wife.
H+W=91.
now let diff between their ages be x.that is H-W=x.
now when husband is W yaers old, his wife must be W-x years
old.and it is given that H=2(W-x). so 2W-H=2x. and H-
W=x.eliminating x we get 4W=3H. but H+W=91, so solving thse
two H=52 W=39.
Answer: 66.67 km approx.
Solution:
Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,
u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr
Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)
total no of 4 wheelers: 40
total no of 2 wheelers: 18
The answer is A)
y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg
y2 – y1 = 10 Rs/kg
The distance between the y and y1 is
y – y1 = 64.5 – 62 = 2.5
x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75
The target price is calculated by the lever method.
x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5
The ratio is of y1 to y2 is
0.75 : 0.25
Divide by both by 0.25
3 : 1
30/70*100=42.87
Actual price is RS.60 and (plus)he got profit of 10%. So 60+ 10%(60) = 66
8
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2hr 30min
option B
TCPEOSPR
13 and 15
when know that 13 is factor of 39 so it will also not be able to divide it differently. so the remainder will be same 20 but as we know that 20 is greater then 13 so we can divide it once again and in the casE of 13 the remainder will be 20-13=7
5! = 120