Mytheresa.com Interview Questions, Process, and Tips

13

Pen

d=7s—–equation 1
d=5(s+12)
7s=5(s+12)
7s=5s+60
2s=60
s=30
from equation 1
d=7*30
d =210km

Given y/x = 1/3, x+2y =10
3y=x
Then substitute x=3y in x+2y=10

3y+2y=10
5y=10
y=2

Then substitute y=2 in x=3y
x=3*2
x=6
: x=6, y=2

3 hours ago.

Thin candle melts 3/4 in 3 hours leaving 1/4
Where as in the same time thick candle melts 3/6 leaving 3/6 which is 1/2. Now thick candle is exactly twice than the thin candle.

Or via modeling:

We need to find time at which the length of the thin candle is half the thick candle. Let x be the time. Thin candle melts at 1/4 an hour and thick candle melts at 1/6 an hour. In x hours they melt at x/4 and x/6 respectively. What’s left will be 1 – x/4 and 1 – x/6. We need to find x at which :

2 * (1 – (x/4)) = 1 – (x/6)

This equation results in x = 3

16

120

⇒ First part = Rs. 828

8:7 ratio

2 urns, 9 balls.
4(2)+1=9 and 3(2)+3=9
You can’t put 4 balls in each of 7 urns with balls left over when 7*4=28. 28>24.

Assume Q can do the work alone in Q days:

work of a day by both P and Q =>
(1/15) + (1/Q ) = 1/6
solving this Q = 10.

x/2y=3/2…
therefore
2x=6y
x=3y
therefor
=21y+4y/3y-2y
=25y/y
=25..
there answer=25
so for the above question, we don’t have an option…so answer
is Data Insufficient..

B

pages # figures
1000 1000 4
from 999 to 100 (999-99)*3 2700
from 99 to 10 (99-9)*2 180
from 9 to 1 (9-0)*1 9
total sum= 2893

3000