Invest ottawa Interview Questions, Process, and Tips

no combinations is there because a number divisible by 36
also divisible by its divisors anu.sum of 4 digits=20,whis
is not multiple of 3.so it is cannot divisible by 3

54

let d distance and s be speed.
d/7 = x and d/5 = x+12
solving we get d=210.

A

Let Suvarna, Tara, Uma and Vibha be S,T,U,V respectively
initially in the beginning each persons share be
V = x U = y T = z
S = w = (x+y+z+32) Reason: She has to double others share, so she should have each and everyone’s share and still should be left out with 32

after 1st Round of game
S loses and is out with 32 and doubles the others share
V = 2x U = 2y T = 2z

After 2nd Round of game
T loses and is out with 32 and doubles the others share
V = 4x U = 4y
This means T had 2z = 2x + 2y + 32
After 3rd round of game
U looses and is out with 32 and doubles others share
V = 8x
This means U initially has 4y = 4x + 32
In the end V = 8x = 32

Solving this we get x = 4, y = 12, z = 32 and w = 80
There fore Suvarna had highest share in the beginning

S=D/T
S=624KM/6.5HRS
S=96KM/HR

900

When none of the digits are repeated:

The hundred’s place can be filled by any of the digits: 2, 3, 5, 6, 7 or 8 except the one which has already been used at the thousand’s place, so it can be filled in 5 ways.

Similarly tens’ place can be filled in 4 ways: only those 4 numbers which have not been use either at hundred’s or thousand’s place.
Unit’s place can be filled in only 3 ways. So, total number of nos. Possible =4×5×4×3= 240

4155

The ans is -20.
Solution:
A-1
B-2
C-3 D-4 …like wise till Z-26.
ELECTRICITY-5+12+5+3+20+18+9+3+9+20+25==129
GAS-7+1+9==27
ELECTRICITY-GAS=129-27-(Minus 2)=100
so
JACK-JILL=(10+1+3+11-(10+9+12+12)-(minus(2))==(-20)

1.7% loss

0