Ques:- A man engaged a servant on the condition that he would pay him Rs.710 and a uniform after a year service. He served only for 8 months and got Rs.460 and a uniform. Find the price of the uniform?
Recent Answer : Added by PRERNA SAHU On 2021-11-13 11:02:18:
ans=13.33
solution: (710/12)*8 – 460
Ques:- A and B enter into a partnership for a year. A contributes Rs.1500 and B Rs.2000. After 4 months, they admit C, who contributes Rs.2250. If B withdraws his contribution after 9 months, how would they share a profit of Rs.900 at the end of the year?
A. 1 : 1 : 1
B. 1 : 2 : 3
C. 6 : 8 : 9
D. 8 : 6 : 9
Recent Answer : Added by narendra On 2022-09-18 09:03:22:
A
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Ques:- One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field?
Recent Answer : Added by Aditya D On 2022-09-21 16:49:44:
area is given by Area of Rectangle = Length of Rectangle*(sqrt((Diagonal of Rectangle^2)-(Length of Rectangle^2)))
so substituting we get area=4*(sqrt((25-16)))
area=4*(sqrt(9))
since area cannot be negative hence we take sqrt of 9 as 3 (as sqrt of 9 is 3 and -3 as well)
area=4*3=12m^2
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Ques:- In a sports contest there were m medals awarded on n successive days (n > 1). 1. On the first day 1 medal and 1/7 of the remaining m – 1 medals were awarded. 2. On the second day 2 medals and 1/7 of the now remaining medals was awarded; and so on.On the nth and last day, the remaining n medals were awarded.How many days did the contest last, and how many medals were awarded altogether?
Recent Answer : Added by DK BOSS On 2021-07-21 15:26:11:
Recent Answer : Added by Admin On 2020-05-17 12:03:27:
( c ) 10
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Ques:- The prime numbers dividing 143 and leaving a remainder of 3 in each case are
A. 2 and 11
B. 3 and 7
C. 5 and 7
D. 11 and 13
Recent Answer : Added by Mbabazi Nuriat On 2022-05-17 08:55:04:
D
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Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:40:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;
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Recent Answer : Added by arjun On 2021-12-09 18:40:02:
60000
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Recent Answer : Added by as On 2021-05-16 16:12:43:
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ans=13.33
solution: (710/12)*8 – 460