CETPA INFOTECH PVT Interview Questions, Process, and Tips

x-28=(1/3)x
x= 42

50 %of 42 = 21

22

France — D

The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.

1(1/7)hr

MONKEY=YEKNOM then each letter is moved backward =XDJMNL so for TIGER=REGIT the each of the reversed letters are moved backward=QDFHS

9936

I think U r wrong Tina,because
according to u,
1st customer=43 apples
2nd customer=21.5 apples
An apple cannot be cut
I think the answer is 127 check it out…

Doug won the race
Explanation-
The ratio of steps covered by me, Doug, and Anne is = 6:7:8

Since Distance covered in Me 21 steps = Distance covered by Doug 24 steps = Distance covered by Anne 28 steps

LCM (21, 24, 28) = 168

For a distance of 168 units, the ratio of the distance covered in each step is;
= 8 : 7 : 6
Therefore the ratio of speeds is;
= 8×6: 7×7: 6×8
= 48 : 49 : 48

Here, the speed of the Doug is more than the speed of me and Anne
Hence, Doug won the race

RABBIT

4 mins