Ques:- In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Recent Answer : Added by Kristi Bardhan On 2022-09-02 17:04:02:
When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters.
Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters.
So, in a race of 1000 meters, A beats C by (1000 – 787.5) = 212.5 meters to C.
So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.
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Recent Answer : Added by Saiteja On 2021-07-29 16:19:16:
2.5 sec
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Recent Answer : Added by Abhishek Chabri On 2022-10-08 07:25:37:
6 inch
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Ques:- A speed of 14 metres per second is the same as
A. 28 km/hr
B. 50.4 km/hr
C. 70 km/hr
D. 74.2 km/hr
Recent Answer : Added by M KISHORE On 2023-03-15 16:31:05:
let convert meter to kilometer by multiply 18/5 then answer be 14*(18/5)=50.4 km/s
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A. 1 : 1 : 1
B. 1 : 2 : 3
C. 6 : 8 : 9
D. 8 : 6 : 9
Recent Answer : Added by narendra On 2022-09-18 09:03:22:
A
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Recent Answer : Added by b On 2021-08-11 19:02:58:
435
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Recent Answer : Added by DK BOSS On 2021-07-21 15:26:40:
it is based on the right shift operation on the perticular digit
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Ques:- A person meets a train at a railway station coming daily at a particular time. One day he is late by 25 minutes, and he meets the train 5 k.m. before the station. If his speed is 12 kmph, what is the speed of the train.
Recent Answer : Added by DK BOSS On 2021-07-30 16:27:20:
Ans: 60 kph
Suppose Person meets the train everyday at 3 PM at Station A.
His speed is 12kph.
So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.
But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.
Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.
So speed of the train is 5KM/5min = 60 kph.
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Ques:- There is a 5digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3 rd digit is 3 less than the second. 4 th digit is 4 more than the second one. Find the digit.
Recent Answer : Added by Admin On 2020-05-17 11:59:40:
let first digit be ‘X’
then 5th digit is ‘3X’
let 2nd digit be ‘Y’
then 3rd digit is ‘Y-3’
and 4th digit is ‘Y+4’
then the no is ‘(X)(Y)(Y-3)(Y+4)(3X)’
from the above we can say 3X<=9
so X<=3 and any of the digit in the number is <=9
and also given that 3 pairs sum is 11...
so make trial and error..
if X=1...any of the no is 10 which is wrong trial....
if X=2...then let Y+4=9 ==> Y=5
then no is 25296
first pair 2+9=11
second pair 2+9=11
third pair 5+6=11
now the answer is 25296
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When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters.
Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters.
So, in a race of 1000 meters, A beats C by (1000 – 787.5) = 212.5 meters to C.
So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.