BYTEFORZA TECHNOLOGIES Interview Questions, Process, and Tips

Ques:- The difference between the ages of two of my three grandchildren is 3. My eldest grandchild is three times older than the age of my youngest grandchild and my eldest grandchild’s age is two years more than the ages of my two youngest grandchildren added together. How old is my eldest grandchild?
Ques:- A is twice as good a work man as B and together they finish the work in 14 days. In how many days A alone can finish the work?
Ques:- Intro and family background.
Ques:- Why do you wish to change your Career Specialization?
Ques:- Which company are you working now?
Ques:- A train passes two cars moving in the direction at 45km/hr and 50km/hr in 36 sec and 54 sec respectively. What is the length of the train?
Ques:- Number Series 3,18,4,24,5,30,?
Recent Answer : Added by Rohini kale On 2021-12-23 16:25:58:

6,36

Ques:- WHAT IS THE IMPORTANCE OF MS EXCEL & MS- WORD AND WHAT ARE ITS MAIN APPLICATION IN COMPANIES
Ques:- How many degrees (if any) are there in the angle between the hour and minute hands of a clock when the time is a quarter past three?
Recent Answer : Added by pooja Jawade On 2021-11-25 15:47:56:

22.5

Ques:- You have 5 jars of pills. Each pill weighs 10 gram, except for contaminated pills contained in one jar, where each pill weighs 9 gm. Given a scale, how could you tell which jar had the contaminated pills in just one measurement?
Recent Answer : Added by Admin On 2020-05-17 12:01:47:

Take 5 pills from jar 1, 4 pills from jar2,…. and 1 pill
from jar 5 and put altogether in the scale. the ideal
weight should be (1+2+3+4+5)x10= 150gms. for eg if the jar2
is contaminated then the weight will be 146 gms. so
depending on the amount of weight loss we can identify the
contaminated jar.

Ques:- Which of the following is always odd?
A. Sum of two odd numbers
B. Product of two odd numbers
C. Difference of two odd numbers
D. None of these
Recent Answer : Added by narendra On 2022-09-18 09:03:02:

B

Ques:- The cost of 10 kg of apples is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is Rs.20.50. Find the total cost of 4 kg of apples, 3 kg of rice and 5 kg of flour?
Recent Answer : Added by AVI On 2021-12-23 16:25:51:

877.4

Ques:- Vision, Mission and future goals as a professional in HR
Ques:- If you won $10 million lottery, would you still work?
Ques:- Raj has a jewel chest containing Rings, Pins and Ear-rings. The chest contains 26 pieces. Raj has 2 and 1/2 times as many rings as pins, and the number of pairs of earrings is 4 less than the number of rings. How many earrings does Raj have?…
Recent Answer : Added by King11 On 2022-03-18 09:20:21:

6 pairs of earrings. So 12 earrings.

The total has to be 26, so let’s say there’s 6 pairs of earrings and the number of pairs has to be 4 less than the number of rings. So that would make 10 rings. The 10 rings has to be 2 1/2 greater than the number of pins. So you would divide 10/2.5 = 4 Pins. That would equate to a total of 12 earrings, 10 rings, and 4 pins. A total of 26 pieces.

Ques:- What is your area of interest?
Ques:- Give me an example of your creativity (analytical skill?managing ability, etc.)
Recent Answer : Added by Gowthamabarani S On 2021-02-24 17:31:38:

no

Ques:- Give an example of something which you don’t do in a conventional way?
Recent Answer : Added by DK BOSS On 2021-07-16 09:52:46:

I am not doing my money investment in conventional manner

Ques:- What r u doing now a days?
Ques:- 2/3 of corckery(plates) are broken, 1/2 have someother thing(handle) broken , 1/4 are both broken and handle broken. Ultimately only 2 pieces of corckery were without any defect. How many crockery were there in total.
Recent Answer : Added by Admin On 2020-05-17 12:02:29:

let no of total crockery =x
2x/3 crockery broken
x/2 handle broken
x/4 both brocken
2x/3+x/2-x/4 = no of total broken(crockery or handle)
=11x/12
unbroken =x-11x/12=x/12
x/12=2(given in question)
x=24

Ques:- What product would you make and how will you sell the idea to your boss in case you are working in a brand selling Laptop mouse?
Ques:- How can you grow international business of organisation & yourself too?
Ques:- You have not been to core accounting
Ques:- Jarius and Kylar are playing the game. If Jarius wins, then he wins twice as many games as Kylar. If Jarius loses, then Kylar wins as the same number of games that Jarius wins. How many do Jarius and Kylar play before this match?
Recent Answer : Added by sk On 2022-08-14 16:41:57:

5 (3+2)
if he wins then it becomes 4 double than 2
and if looses then opponent becomes 3 which is equal.

Ques:- How do you deal with stress?
Ques:- Describe to me in detail a time when you took the initiative in a major project.
Ques:- What would you like to do five years from now?
Ques:- Examination passed from and either training was done or not?
Ques:- There is a 50m long army platoon marching ahead. The last person in the platoon wants to give a letter to the first person leading the platoon. So while the platoon is marching he runs ahead, reaches the first person and hands over the letter to him and without stopping he runs and comes back to his original position. In the mean time the whole platoon has moved ahead by 50m. The question is how much distance did the last person cover in that time. Assuming that he ran the whole distance with uniform speed.
Recent Answer : Added by Admin On 2020-05-17 12:00:37:

The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.

Ques:- Where was the capital of Kanishka?
A. Purushapura
B. Kannauj
C. Taxila
D. Kandhar

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Devendra Bhardwaj With a decade of experience as a Job Hiring Expert, I am a results-driven professional dedicated to elevating recruitment strategies. My expertise lies in navigating the dynamic landscape of talent acquisition, employing innovative approaches to attract, assess, and secure top-tier candidates. I excel in optimizing hiring processes, leveraging cutting-edge technologies, and fostering collaborative relationships with stakeholders. A keen understanding of industry trends allows me to stay ahead, ensuring a competitive edge in securing the best talent for your organization. I am passionate about connecting the right people with the right opportunities and thrive in creating impactful, streamlined recruitment solutions.

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