Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:40:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;
Ques:- The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs. 20 per kg. if both Type I and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is
A. Rs. 18
B. Rs. 18.50
C. Rs. 19
D. Rs. 19.50
Recent Answer : Added by narendra On 2022-09-18 09:02:19:
a
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Recent Answer : Added by ramathota madhu On 2022-03-09 16:36:28:
w, l=2w , area of square =8^2 = 64
area of rectangle = l*b
so w*2w = 8*64
w=16
length = 32
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I agree with @TUMWINE PETER
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Ques:- if 30 men completes a job in 15 days working 9 hrs per day.. how much hours per day should 40 men work ??
Recent Answer : Added by Admin On 2020-05-17 12:04:31:
as i assume the time taken to complete the job is not to be
changed while increasing the employees as it does not
clearly states so……….
30 men wrk for 9 hrs
therefore for the work to be done if no of workers is
increases the no of hrs / day to work should decrease so
here s a inverse relation
solving further we get
30 = K /9 ==> K= 270
now
40 = 270/y ==> y= 6.75
therefore ans is d)none
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A. Rs. 7000
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Recent Answer : Added by Chathura On 2022-05-17 09:09:31:
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Recent Answer : Added by vignesh On 2021-03-02 17:09:32:
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Recent Answer : Added by Admin On 2022-09-29 19:09:33:
Calculation:
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the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;