AG Barr Interview Questions, Process, and Tips

let the amount of money be x

cloths 1/3 X x=rs.x/3

balance = x- x/3 = 2x/3

food = 1/5 X 2x/3 = 2x/15

balance = 2x/3 – 2x/15= 8x/15

travel = 1/4 X 8x/15 = 2x/15

now he has 100 rupees

2x/5 = 100
2x= 500
x = 500/2
x = 250

The answer is A)

y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg

y2 – y1 = 10 Rs/kg

The distance between the y and y1 is

y – y1 = 64.5 – 62 = 2.5

x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75

The target price is calculated by the lever method.

x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5

The ratio is of y1 to y2 is

0.75 : 0.25

Divide by both by 0.25

3 : 1

6+3.50= 2.50

these are question tht are seem to be like it consumes
time. so dont see jus the question and run to the next .

ans. a) 12

if 9 balls are added then the ratio to the combination
becomes 2:4:3.

9 balls make the ratio 3 for grey balls in tht mixture.
so the factor is 9/3 = 3 (in tht mixture)

so the same factor has to be maintained through out the
ratio. so black balls is 4 * 3 = 12 and white balls is 2 *
3 = 6.

TWICE

400

pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144×100)/60
X=240
total students=240

37

The number is greater than the number obtained in reversing the digits and the ten’s digit is greater than the unit’s digit
Let ten’s and unit’s digit be 2x and x respectively
Then, (10×2x+x)−(10x+2x)=36
9x=36
x=4
Required difference=(2x+x)−(2x−x)=2x=8

let present age of ANAND AND BALA BE( A AND B ) RESPECTIVELY

A.T.Q

(A-10) = 1/3[B-10]. ……… – {1}

given

B = A+ 12 PUTTING IN 1

THEREFORE A-10 = 1/3 (A+2) = A+2 = 3A – 30

2A =32

A=16

answer :36