Ques:- The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
Ques:- If a car starts from A towards B with some velocity due to some problem in the engine after travelling 30km.If the car goes with 4/5 th of its actuval velocity the car reaches B 45min later to the actual time. If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual time , what is the initial velocity of car and what is the distance between A and B in km
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:31:
Ans. let x is distance from A to B
and y is initial speed.
30/y+(x-30)5/4y -x/y = 3/4
=> 4x-12y=120 —-(1).
45/y + (x-45)5/4y -x/y=3/5
=> 5x-12y=225 ——-(2).
From equ (1) and equ (2) we will get.
x=25 and y=105
so initial speed is 25 km/hr
and Distance From A to B is 105 km
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Recent Answer : Added by Hari Shankar yadav On 2022-08-14 16:35:46:
In plan A 7500/- and other amounts in plan B
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Ques:- There is a 50m long army platoon marching ahead. The last person in the platoon wants to give a letter to the first person leading the platoon. So while the platoon is marching he runs ahead, reaches the first person and hands over the letter to him and without stopping he runs and comes back to his original position. In the mean time the whole platoon has moved ahead by 50m. The question is how much distance did the last person cover in that time. Assuming that he ran the whole distance with uniform speed.
Recent Answer : Added by Admin On 2020-05-17 12:00:37:
The last person covered 120.71 meters.
It is given that the platoon and the last person moved with
uniform speed. Also, they both moved for the identical
amount of time. Hence, the ratio of the distance they
covered – while person moving forward and backword – are
equal.
Let’s assume that when the last person reached the first
person, the platoon moved X meters forward.
Thus, while moving forward the last person moved (50+X)
meters whereas the platoon moved X meters.
Similarly, while moving back the last person moved [50-(50-
X)] X meters whereas the platoon moved (50-X) meters.
Now, as the ratios are equal,
(50+X)/X = X/(50-X)
(50+X)*(50-X) = X*X
Solving, X=35.355 meters
Thus, total distance covered by the last person
= (50+X) + X
= 2*X + 50
= 2*(35.355) + 50
= 120.71 meters
Note that at first glance, one might think that the total
distance covered by the last person is 100 meters, as he
ran the total lenght of the platoon (50 meters) twice.
TRUE, but that’s the relative distance covered by the last
person i.e. assuming that the platoon is stationary.
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E. None of these
Recent Answer : Added by Laya Augustine On 2022-09-15 16:35:51:
sister
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Recent Answer : Added by Maddipatla Sai Kumar Naidu On 2022-11-08 16:21:49:
28 hrs
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CITOXE
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Recent Answer : Added by Shaik Mohammad Javeed On 2021-11-18 17:15:42:
C)1440
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12*4=48
48*5=240
240*6=1440
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Recent Answer : Added by Iniobong On 2022-08-14 16:44:16:
A
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A. Brother
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E. None of these
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A. 2
B. 3
C. 4
D. 6
Recent Answer : Added by Admin On 2022-09-23 18:52:00:
C. 4
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Ques:- On Monday a banker processed a batch of cheques, on Tuesday she processed three times as many, and on Wednesday she processed 4000 cheques. In the three days, she processed 16000 cheques. How many did she process on Tuesday?
Recent Answer : Added by Davemark Kigen On 2021-09-28 17:28:21:
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Ans. let x is distance from A to B
and y is initial speed.
30/y+(x-30)5/4y -x/y = 3/4
=> 4x-12y=120 —-(1).
45/y + (x-45)5/4y -x/y=3/5
=> 5x-12y=225 ——-(2).
From equ (1) and equ (2) we will get.
x=25 and y=105
so initial speed is 25 km/hr
and Distance From A to B is 105 km