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HCF = 2
LCM = 70
Let the two numbers be 2a and 2b
(Since HCF is 2, both numbers must be divisible by 2)
So,
LCM of 2a and 2b = 2ab
And the product of the numbers = 2a × 2b = 4ab
Now,
We know:
Product of the two numbers = HCF × LCM
⇒ 4ab = 2 × 70 = 140
⇒ ab = 35
Now we need to find two numbers a and b such that:
ab = 35
and a, b are co-prime (because HCF of original numbers is already taken as 2)
Factors of 35 that are co-prime:
1 × 35, 5 × 7
Try a = 5, b = 7
⇒ Numbers = 2a = 10 and 2b = 14
Or vice versa: 14 and 10
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✅ Final Answer: The two numbers are 10 and 14.