12(1/3) = 4 so women = 4
==>men = 12-4 = 8
if team needs 20% of women then men Will be 80%
consider u want to hire “x” men
so,
(12+x)(80/100) = 8 + x
so, x= 8
Explanation:
The number of ways of selecting three men, two women and three children is:
= ⁴C₃ * ⁶C₂ * ⁵C₃
= (4 * 3 * 2)/(3 * 2 * 1) * (6 * 5)/(2 * 1) * (5 * 4 * 3)/(3 * 2 * 1)
= 4 * 15 * 10
= 600 ways.
12 %
d=5
g=1
a=4, b=6,c=2,d=5,e=8,f=3,g=1,h=9,i=7
2880, 480, 92, 24, 8, 4, 4
4×1 = 4
4×2=8
8×3=24
24×4= 96 (not 92)
96×5 =480
480×6= 2880
So answer is 92
Six men can at a time put mangala sutra (marriage) to their
spouses where six women cant do
x/y =5/7…………………………..(1)
(x-25)/(y-25)=35/39
59x=35y+600
dividing b.t.s by y and substituting (x/y) value from equation (1)
y=84
Now, substitue y value in equation (1)
x = 60
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds
I will reading IPad questions and Awsome
b
Sachin is 14 years old whereas Rahu is 18 years old.
c