Ques:- A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
Ques:- 125 : 216 :: 1331 : __
Recent Answer : :
1728
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Ques:- The H.C.F. and L.C.M. of two numbers are 50 and 250 respectively. If the first number is divided by 2, the quotient is 50. The second number is
A. 50
B. 100
C. 105
D. 125
Recent Answer : :
125
Ques:- Position in this company
Ques:- The PSLV-C12 was successfully launched into space from t h e Satish Dhawan Space Centre at Sriharikota on 28 April, 2009. PSLV stands for?
Ques:- If a 200 m long train crosses a platform of the same length as that of the train in 20 seconds, then the speed of the train is
A. 50 km/hr
B. 60 km/hr
C. 70 km/hr
D. 72 km/hr
Recent Answer : :
3600 sec in 1 hr.. 1000 M in 1 km so to covert m/s to km /hr you multiply the value with (3000/1000) .. so 3000 divided by 1000 will give you 18/5 it’s like constant value.. to convert m/s to km/ hr we can use this 18/5.. hope you understand
Ques:- The sum of four consecutive even numbers is 292. Evaluate the smallest number?
Recent Answer : :
Thanq saddha
Ques:- Personal Information
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Ques:- ?Ghasiram Kotwal? was written by
Ques:- A sum of money lent out at S.I. amounts to Rs. 720 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is?
Recent Answer : :
600
Ques:- Evaluate 33.33% of 27.
Recent Answer : :
9
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Ques:- There are four prime numbers written in ascending order of magnitude. The product of the first three is 7429 and of the last three is 12673. Find the fourth number?
Recent Answer : :
17,19,23,29
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Ques:- In a partnership between P, Q and R. P’s capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and R’s share is Rs.130, what is Q’s capital?
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Ques:- A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Recent Answer : :
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
=>800+x=653∗60=>800+x=20∗65=1300=>x=1300−800=500
Ques:- A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally?(a) 110 men(b) 130 men(c) 100 men(d) none of these
Recent Answer : :
none of these
there will be 20 men
Ques:- What is the correct chronological order of the following Mughal Kings?
A. Babar, Akbar, Jahangir, Humayun
B. Akbar, Jahangir, Babar, Humayun
C. Babar, Humayun, Akbar, Jahangir
D. Humayun, Babar, Akbar, Jahangir
Recent Answer : :
C
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Ques:- A room is 30 X 12 X 12. a spider is ont the middle of the samller wall, 1 feet from the top, and a fly is ont he middle of the opposite wall 1 feet from the bottom. what is the min distance reqd for the spider to crawl to the fly.
Recent Answer : :
length is 30 breadth is 12 and height is 12
——————————
1
.——————————
1 .
1 .
1 10 .
1
1 .
1
1
1 30 .
——————————-.
1
consider right angled triangle
so the distance= square root of (30*30+10*10)
Ques:- Information about Deloitte Touche Tomatso
Hint: Assume that the speed of the stream is x and the speed of the boat in still water is x. From the statement of the question form two equations in two variables x and y. This system is reducible to linear equations in two variables. Reduce the system to a system of linear equations in two variables by proper substitutions. Solve the system of equations using any one of the methods like Substitution method, elimination method, graphical method or using matrices. Hence find the value of x satisfying both the equation. The value of x will be the speed of the stream.
Complete step-by-step answer:
Let the speed of the stream be x, and the speed of the boat in still water be y.
We have the speed of the boat upstream = y-x.
Speed of the boat downstream = y+ x.
Now since it takes 14 hours to reach a place at a distance of 48 km and come back, we have the sum of the times taken to reach the place downstream and time taken to return back upstream is equal to 14.
Now, we know that time =Distance speed
Using, we get
Time taken to reach the place =48y+x and the time taken to return back =48y−x.
Hence, we have
48y+x+48y−x=14
Dividing both sides by 2, we get
24y+x+24y−x=7 —–(i)
Also, the time taken to cover 4km downstream is equal to the time taken to cover 3km upstream.
Hence, we have 4y+x=3y−x
Transposing the term on RHS to LHS, we get
4y+x−3y−x=0 ——– (ii)
Put 1y+x=t and 1y−x=u, we have
24t+24u=7 ——-(iii)4t−3u=0 ——–(iv)
Multiplying equation (iv) by 6 and subtracting from equation (iii), we get
24t−24t+24u+18u=7⇒42u=7
Dividing both sides by 42, we get
u=742=16
Substituting the value of u in equation (iv), we get
4t−3(16)=0⇒4t−12=0
Adding 12 on both sides, we get
4t=12
Dividing both sides by 4, we get
t=18
Reverting to original variables, we have
1y+x=18 and 1y−x=16
Taking reciprocals on both sides in both equations, we have
y+ x=8 ——- (v)y−x=6 ——–(vi)
Adding equation (v) and equation (vi), we get
2y=14
Dividing both sides by 2, we get
y=7.
Substituting the value of y in equation (v), we get
7+x=8
Subtracting 7 from both sides we get
x = 8-7 =1
Hence the speed of the stream is 1 km/hr.