Provakil Technologies Interview Questions, Process, and Tips

3:4
3x:4x
3x+4x=420
7x=420
x=60

smaller number=3(60)=180.

Total 60 trees
4 rows each with 15 trees
5 rows each with 12 trees
6 rows each with 10 trees

Ans 635.5
4000
1 year 5 % 200 rs int
Total 4200
2 year 5 % 210 ra int
Total 4410
4410-2210 = 2200
1 year 5% 110
Total 2310
2 year 5 % 115.5 rs int
Total 2425.5
Total interest paid
200 +210+ 110+115.5. = 635.5

3

1:2

let the speed limit be x.
speed by first rider S1 and 2nd rider be S2.
S1=x+10;
ans S2=x+2*10; and given S2=35.
solving we get x=15mph.

A certain sum amounts to Rs. 1725 in 3 years

and amounts to Rs.1875 in 5 years

so interest of 2 years = 1875 -1725

= 150

so interest of 1 year = 75

so interest of 3 years = 75 × 3 =225 rs

so , Principal = Amount – SI

= 1725 – 225

= 1500 rs

now ,

S.I. = P × N × R /100

75 = 1500 × 1 × R /100

R = 75 / 15

R = 5%

Let the person ate x banana on first day, so below is the equation for five days
X+x+6+x+12+x+18+x+24=100
So, he ate 8 banana first day

3:7

9 its just like popcorn box in cineme everyone take large leaving medium
aside

the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;

23. 15s squre is 225and 8 squre is 64 addition is 289 product also 120 addition 15+8=23

say the work is w and let no of days taken by b is ‘x’ which
we have to calculate
so work done by a in one day is w/6
work done by b in one day is w/x
a and b together can do work in 4 days ie=(w/6)+(w/x)=(w/4)
solving equation x=12
so no of days taken by b=12