Amoco Interview Questions, Process, and Tips

11 times in 12hours

192 zeros in 1 to 1000

6

4.5

1600 years contain 0 odd day.
300 years contain 1 odd day.
94 years = (23 leap years + 71 ordinary years)
= (46 + 71) odd days
= 117 odd days, i.e., 5 odd days
Days from 1st January 1995 to 28th February 1995
= (31 + 28) days = 59 days
= (8 weeks + 3 days) = 3 odd days
∴ Total number of odd days
= (0 + 1 + 5 + 3) = 9 odd days i.e., 2 odd days.
So, the required day is Tuesday.

I solve it as the 280m train being stationary… and the 120m train moving at (42+30) = 72kph…. or 20mps

The front of the train will have to go 280m to pass the stationary train plus another 120m for the backs to clear… that is 400m in all.

The time to travel 400m at 20mps is 20secs

40 km avrege speed

Hog

Distance covered by B to meet A=Total distance – Distance covered by A hrs

[using : distance = speed x time]

Putting value of from equation (1),

hrs

Therefore, time at which both A and B will meet is = 7 a.m. + 3 hrs =10 am

(3/4)*(L/Sp)=30
L/Sq=75
(3/4)*(Sq/Sp)=30/75
Sq/Sp=8/15
Sp/Sq=15/8

Doug won the race
Explanation-
The ratio of steps covered by me, Doug, and Anne is = 6:7:8

Since Distance covered in Me 21 steps = Distance covered by Doug 24 steps = Distance covered by Anne 28 steps

LCM (21, 24, 28) = 168

For a distance of 168 units, the ratio of the distance covered in each step is;
= 8 : 7 : 6
Therefore the ratio of speeds is;
= 8×6: 7×7: 6×8
= 48 : 49 : 48

Here, the speed of the Doug is more than the speed of me and Anne
Hence, Doug won the race

10m

trick
(r/10)*(r/10)
(20/10)*(20/10)
4% decrese