Ojas Innovative Technologies Interview Questions, Process, and Tips

1/24S

the answer is 45 km/h
Define x:

Let the total distance be x.

Find the time needed in terms of x for speed at 30 km/h:
Find the time needed in term of x for 40 km./h:
Find the difference in time:
Solve x:
Find the total time needed to for the whole journey:
Given that he was 40 mins late:
Find the minimum speed needed:
Answer: The minimum speed is 45 km/h

6 cuts

let convert meter to kilometer by multiply 18/5 then answer be 14*(18/5)=50.4 km/s

B. No such pair exists

16 poles per min
48kmph=48000 meters per hr
=800 meters per min
800/50=16 poles per min

To solve this problem, we can break it down into steps:

Step 1: Determine the individual rates of work for A, B, and C.

If A needs 8 days to finish the task, then their work rate is 1/8 of the task per day.
If B needs 12 days to finish the task, then their work rate is 1/12 of the task per day.
If C needs 16 days to finish the task, then their work rate is 1/16 of the task per day.

Step 2: Calculate the combined work rate of A and B.

If A works for 2 days, their contribution will be 2 * (1/8) = 1/4 of the task completed.
If B works until 25% of the job is left for C, then they will complete 75% of the task.

Step 3: Calculate the time it takes for B to complete 75% of the task.

Since B’s work rate is 1/12 of the task per day, it will take B (75%)/(1/12) = 9 days to complete 75% of the task.

Step 4: Calculate the remaining work for C.

If B completes 75% of the task, then the remaining work for C is 100% – 75% = 25% of the task.

Step 5: Calculate the time it takes for C to complete the remaining work.

Since C’s work rate is 1/16 of the task per day, it will take C (25%)/(1/16) = 4 days to complete the remaining 25% of the task.

Step 6: Calculate the total time required.

A worked for 2 days, B worked for 9 days, and C worked for 4 days, totaling 2 + 9 + 4 = 15 days.

Therefore, it will take a total of 15 days for A to work for 2 days, B to work until 25% of the job is left, and C to complete the remaining work.

119

4500 sal of jan

4 days

33

Balls- B1, B2, B3, B4, B5, B6, B7, B8, B9.
Group1 – (B1, B2, B3), Group2 – (B4, B5, B6), Group3 – (B7, B8, B9)
Now weigh any two groups. Group1 on left side of the scale and Group2 on the right side.
When weighing scale tilts left – Group1 has a heavy ball or right – Group2 has a heavy ball or balanced – Group3 has a heavy ball.
Lets assume Group 1 has a heavy ball.
Now weigh any two balls from Group1. B1 on left side of the scale and B2 on right side.
When weighing scale tilts left – B1 is the heavy or tilts right – B2 is the heavy or balanced – B3 is the heavy.

% error= (new no-actual no)/actual no *100
% error= [(x/7)-7x]/7x * 100
% error= 48x/49x * 100
% error= 0.9795*100=97.95

1:2:3 or 1:2:4