OCRex Enterprises Interview Questions, Process, and Tips

20&130

Marks in thrice in english as in science
so if science marks is x
then english marks = 3x
lets maths marks = y
ratio of english and maths marks is
3x/y = 3/5
=> y = 5x

and total marks = 162
3x + x + 5x = 162
x = 18 —-answer

10C3 = 120

Answer: 3121 gold coins
Let total no of coins be M
Let the disbursement D to each son:

D1 = 1 + (M – 1)/5 = (M + 4)/5
D2 = 1 + ( M – D1 -1)/5 = (D1) * 4/5
D3= (D2) * 4/5
D4= (D3) * 4/5
D5= (D4) * 4/5
Total disbursements to sons=
= ∑D= (M+4)*1/5[ 1+4/5+(4/5)(4/5)+ (4/5)(4/5)(4/5)+(4/5)(4/5)(4/5)(4/5) ]
= (2101/3125)*(M+4)
Thus balance left for daughters =M-{(2101/3125)*(M+4)}
=(1024M-8404)/3125
This balance should be a positive integer ( assuming M and all disbursements are full coins )
Thus 1024M-8404 should be a multiple of 3125….so….
1024M – 8404 = N*3125 where N is an integer
Using Python code:
n=int(input(“Enter num n: “))
X=int()
a=int()
a=0
X=’ ‘
for a in range(0,n+1):
a=a+1
X= (3125*a + 8404)/1024
if (3125*a + 8404)% 1024== 0:
print(X,a)
Enter num n: 10000
3121.0 1020
6246.0 2044
9371.0 3068
12496.0 4092
15621.0 5116
18746.0 6140
21871.0 7164
24996.0 8188
28121.0 9212
We get minimum value of N = 1021 and M = 3121 gold coins

(C*D)/G

ans: 250 rs exactly

take goat from one side and leave it another side and then come back another side and carry cabbage from one side leave it near goat and carry goat back to other side and then carry wolf leave it another side with cabbage come back to
goat side and carray goat to other side not all three are there on another side

35Kg

60*5/18*9=150

5! = 120

9 its just like popcorn box in cineme everyone take large leaving medium
aside

16

D