xy+2y-x=6
xy+2y-x-2=6-2
y(x+2)-1(x+2)=4
(y-1)(x+2)=4
so c is 4
I WOULD STRIVE TO MAKE THE GOOGLE SEARCH MORE RESPONSIVE
TOWARDS THE QUESTIONS, AS THE GOOGLE RESULT JUST CONTAIN
THE SITE RELATED TO THE TERMS INCLUDED.
Total number of pairs is NC2^{N}C_2NC2. Number of pairs standing next to each other = N. Therefore, number of pairs in question = NC2^{N}C_2NC2 – N = 28/2 = 14. If N = 7,
7C2 – 7 = 21 – 7 = 14….
N =7
24 Kmp/h
By 1hour both trains meet, so the distance travel by fly in
1hr is 120km.
I would say everyone has blind spots, and i would too. And that is why I believe in teamwork because when you are a team, you can point out other people’s blind spots and they will do the same for you.
option D
6084
7431 is largest number and 1347 is the least number from digits 1,3,4,7
so 7431-1347=6084
10
The batsman on 98 is on strike. He hits the ball and they run 3. UNFORTUNATELY one of the batsmen doesn`t turn correctly for one of the runs and the umpire calls ONE SHORT and awards only two runs. Therefore the first batsman has his century. There is now 1 ball remaining and one run is required to win. The batsman on strike, however is now the one on 97 runs. He now either hits a 4 or a 6. They win the game and both batsmen scored centuries.
Read more: 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries … – 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries as well win the match ?
DISTANCE=TIME *SPEED
D=?
48*(5/18)=13.33m/s
D=9*13.333=120m