MixerBox Interview Questions, Process, and Tips

90 degree

0

The numbers that lie between 100 and 1000 which are divisible by 14 are 112, 126,140 …,994
a = 112; l = 994, d = 14
n= (l−a)/d+1
= (994-112)/14+1
= 64
Sn=n/2(l+a)
= 64/2(994+112)
= 32*1106
= 35392

810

2:3

Robin =72
Dravid = 98
Azhar = 22
Sachine = 98
Total score = 290

27

12

9000

if A is true B has to be true

That person’s struggle and dream to achieve something motivates the person.

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​

1506

15,25

88

16

number1*number2=lcm*hcf
so,
product of two numbers is ,

2025=lcm*15
lcm=2025/15
lcm=135