Memset hosting Interview Questions, Process, and Tips

12 %

240 m

Avg = 2(X*Y)/X+Y
2*(60*40)/60+40
2*(2400)/100
2*24
48.

ans 810 i think

let x be the avg age of each person in the family ten years
back…
so total age=6x
after 10 years i.e,now the total age of the family =6x+60
let grand father age as y
then the average of the family=(6x+60-y)/5
(bcoz grand father has expired and the new born baby has no
age at present)
according to the given question (6x+60-y)/5=x
bcoz x is the avg age bfore 10 years.
while calc the equation according to the presnt age we have
to add 10 to the result….
so the answer is 70

C

bogus, counterfeit, fake, false, illegitimate, sham, unreal

let first digit be ‘X’
then 5th digit is ‘3X’
let 2nd digit be ‘Y’
then 3rd digit is ‘Y-3’
and 4th digit is ‘Y+4’
then the no is ‘(X)(Y)(Y-3)(Y+4)(3X)’
from the above we can say 3X<=9 so X<=3 and any of the digit in the number is <=9 and also given that 3 pairs sum is 11... so make trial and error.. if X=1...any of the no is 10 which is wrong trial.... if X=2...then let Y+4=9 ==> Y=5
then no is 25296
first pair 2+9=11
second pair 2+9=11
third pair 5+6=11
now the answer is 25296

If there are n bikes then the no. of people are 2n+1. n are dropped in firs trip, in second trip 3 bikes are unused, so 2n-3 + n covers 2n+1 people. i.e. n + 2n – 3 = 2n +1
n = 4
No. of people = 9

7/5 * 5/q = 7/10
35/5q = 7/10
q=10

C

cannot be determined .

10 a.m.

10%