Ques:- Past Experience, Family status and new challenges
Ques:- A school is going to have 1000 students in near future. 1/4th use scooter, 1/5th use bikes and 1/9th use cycle. Find the number of students at present.
Recent Answer : Added by Pijus Ghosh On 2021-12-17 16:08:32:
562.
Ques:- 100 glasses are there. A servant has to supply glasses to a person If he supplies the glasses without any damage he will get 3 paise otherwise he will loose 3 paise. At the end of supplying 100 glasses if he gets 270 paise, how many glasses were supplied safely.
Recent Answer : Added by Admin On 2020-05-17 12:02:10:
Suppose that x glassses are supplied safely , therefore
(100-x) glases are damage. Then equation is :
3x – 3(100-x) = 270
on solving this equation value of x comes out to be 95.
Ques:- A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Recent Answer : Added by Jay On 2022-08-14 16:45:18:
28 Sec
Ques:- The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then what is the value of x ?
Recent Answer : Added by Lavish Garg On 2022-08-14 16:31:11:
16
Ques:- What if the interviewer ask that we are offering 8000 only but if another company is offering 10000 would you like to go?
Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Recent Answer : Added by Ben Gulliano On 2023-05-23 15:53:20:
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds
Ques:- Asked about qualification details?
Ques:- If there are 1024*1280 pixels on a screen and each pixel can have around 16 million colors. Find the memory required for this?
Ques:- A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
Ques:- X and Y together can do a piece of work in 8 days. If X alone can do the same work in 12 days, then Y alone can do the same work in?
Recent Answer : Added by Kanon Kamronnaher On 2022-08-14 16:36:02:
24 days
Ques:- The size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds / and response will be back to programmer in 20 millisecond. How many much time the program takes to get a response back to programmer, after it is sent? Plz explain..
Recent Answer : Added by 9074743593 On 2021-07-29 16:19:39:
30
Ques:- A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?
Recent Answer : Added by polo On 2020-11-19 16:12:30:
b=15,l=10 or b=10,l=15
Ques:- How to answer freshers “tell me about your self?”
Ques:- Tell me something about your family?
Ques:- P and Q together can do a work in 6 days. If P alone can do it in 15 days. In how many days can Q alone do it?
Recent Answer : Added by Nishara Pathirana On 2023-04-18 07:32:50:
Assume Q can do the work alone in Q days:
work of a day by both P and Q =>
(1/15) + (1/Q ) = 1/6
solving this Q = 10.
Ques:- A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is?
Recent Answer : Added by Atif On 2022-12-05 16:13:31:
3000(4x/100) + 5000(2x/100)=10
Ques:- The prob of finding the parking slot occupied is 1/3. U find it empty for 9 consecutive days. Find the prob that it will be empty on the 10th day.
Ques:- 36 people {a1, a2, …, a36} meet and shake hands in a circular fashion. In other words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3}, …, {a35, a36}, {a36, a1}. Then size of the smallest set of people such that the res…
Recent Answer : Added by Admin On 2022-09-28 17:54:42:
answer is 12
bcoz
there are 36 people and atmost he can shake for 3 people so
36/3=
12
Ques:- A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective?
Ques:- Which is better to grow plants in Rock sand or soil?
Ques:- Among P, M, R, T and J, M is older than R and T. J is older than M and is not the oldest. Who is the youngest?
Recent Answer : Added by Admin On 2020-05-17 12:03:35:
( c ) R or T
Ques:- Write a program to get a count of alphabets from an array of names?
Ques:- What is a percent of b divided by b percent of a?
Ques:- Three men start together to travel the same way around a circular track of 11 kilometers in circumference. Their speeds are 4, 5 and 8 kilometers per hour respectively. When will they meet at a starting point?
Recent Answer : Added by Lokanadham Ponapati On 2021-01-02 15:35:20:
Circular Track sis of 11 km
Speed of Mens are
4 , 5.5 , 8 km/hr
Time at Which they are at starting Points again
11/4 , 11/5 , 11/8
11/4 , 2.2 , 11/8
We need to find LCM of these
to find at what time they Meet again at starting point
LCM 11 * 2 = 22
After 22 Hrs they will meet at starting point
Ques:- What do you like (not like) in this job?
Ques:- WHAT ARE YOUR INTERESTING SUBJECTS
Ques:- There are 4 people in a closed room and you are waiting outside to enter into the room. You can enter only when one of them opens the door. The probability that somebody will open the door is 1/2. Now what is the probability that the door will be opened so that you can go inside?
Recent Answer : Added by Ashwin GB On 2021-07-08 16:28:54:
The probability that no one opens the door would be
0.5×0.5×0.5×0.5= 0.0625
So, the probability that atleast one opens the door is 1-0.0625= 0.9375
Ques:- If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then how many artists r required to make 25 paintings using 25 canvases in 25 days?
To provide the best experiences, we use technologies like cookies to store and/or access device information. Consenting to these technologies will allow us to process data such as browsing behavior or unique IDs on this site. Not consenting or withdrawing consent, may adversely affect certain features and functions.
Functional
Always active
The technical storage or access is strictly necessary for the legitimate purpose of enabling the use of a specific service explicitly requested by the subscriber or user, or for the sole purpose of carrying out the transmission of a communication over an electronic communications network.
Preferences
The technical storage or access is necessary for the legitimate purpose of storing preferences that are not requested by the subscriber or user.
Statistics
The technical storage or access that is used exclusively for statistical purposes.The technical storage or access that is used exclusively for anonymous statistical purposes. Without a subpoena, voluntary compliance on the part of your Internet Service Provider, or additional records from a third party, information stored or retrieved for this purpose alone cannot usually be used to identify you.
Marketing
The technical storage or access is required to create user profiles to send advertising, or to track the user on a website or across several websites for similar marketing purposes.
562.