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This page contains the most recently asked technical questions and answers in the Lister Digital.

All of the questions listed below were collected by students recently placed at Lister Digital.

**Ques:- A train travelling at a speed of 90 km/hr, crosses a pole in 10 seconds. The length of the train is**

**Ques:- An integer us divisible by 16 if and only if its last X digits are divisible by 16. The value of X would be**

**Recent Answer**: :

4

**Ques:- How many times in a day, are the hands of a clock in straight line but opposite in direction?**

**Recent Answer**: :

B

**Ques:- A husband and wife has a combined age of 91.the husband is now twice as old as his wife was when he was as old as she is now. How old are they?**

**Recent Answer**: :

ans is C.

let H be present age of husaband.W be present age of wife.

H+W=91.

now let diff between their ages be x.that is H-W=x.

now when husband is W yaers old, his wife must be W-x years

old.and it is given that H=2(W-x). so 2W-H=2x. and H-

W=x.eliminating x we get 4W=3H. but H+W=91, so solving thse

two H=52 W=39.

**Ques:- Perimeter of the back wheel = 9 feet, front wheel = 7 feet on a certain distance, the front wheel gets 10 revolutions more than the back wheel .What is the distance?**

**Recent Answer**: :

Let the revolutins made by bigger wheel is: x

then revolution by smaller wheel will be: x+10

Now, the distance covered by both wheels will be same.

So,

7(x+10)=9x

7x+70=9x

70=2x

35=x

so distance travelled=9*35=315

or 7*45=315

**Ques:- A>B, B>C, C=D, D>E, then which is greatest**

**Recent Answer**: :

Example 1:

Assign, A=20, B=10, C=5, D=5(Because C is equal to D as

given), E=1.

A/B = 20/10 = 2. So A/B = 2

A/C = 20/5 = 4. So A/C = 4

A/E = 20/1 = 20. So A/E = 20

Therefore “A/E is Greatest”

Example 2:

Assign, A=100, B=50, C=20, D=20(Because C is equal to D as

given), E=10.

A/B = 100/50 = 2. So A/B = 2

A/C = 100/20 = 5. So A/C = 5

A/E = 100/10 = 10. So A/E = 10

Therefore “A/E is Greatest”

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**Ques:- A football team played 60 matches out of which 30% were won by them. If they start winning all the next matches after how many matches will the average winning rate be 50% ?**

**Recent Answer**: :

Matches played: 60.

Matches won: 30% of 60 => (60*(30/100)) = 18 matches.

Iterative approach:

On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So

19 / 61 = 0.3114754098360656

20 / 62 = 0.3225806451612903

21 / 63 = 0.3333333333333333

22 / 64 = 0.34375

…

…

…

…

Similarly,

41 / 83 = 0.4939759036144578

42 / 84 = 0.5

So, after 60th match 24 more matches has to be played and won to get 50% average winning rate.

**Ques:- Given n people live in n houses and at some instant all of them disappear and reappear in some other house. What is the probability that no two meet each other.**

**Ques:- A computer shop consists 3 brands laptop. Laptop of brand A is sold 3/16, B is sold 1/16 and C is sold 3/4 then what fraction is sold by the shop in all.**

**Recent Answer**: :

Answer: 1 / 3

Lets say each brand had 16 laptops

So Sold : A = 3 , B= 1 and C = 12 , total sold: 16 ,

Since each brand has 16 , total = 48

so 16/ 48 = 1/3 is the sold fraction

**Ques:- Describe our city(hyderabad) in a topic round during theinterview time?**

**Ques:- What is your achivment?**

**Ques:- In a group of 15,7 have studied Latin, 8 have studied Greek, and 3 have not studied either.How many of these studied both Latin and Greek**

**Recent Answer**: :

Given:

In a group of 15 students,

7 have studied Latin,

8 have studied Greek,

3 have not studied either.

To find:

The number of students who studied both Latin and Greek.

Solution:

In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.

Therefore,

n(A∪B) = 15 – 3

n(A∪B) = 12

7 have studied Latin,

n(A) = 7

8 have studied Greek,

n(B) = 8

n(A∩B) is the number of students who studied both Latin and Greek.

n(A∩B) = n(A) + n(B) – n(A∪B)

n(A∩B) = 7 + 8 – 12

n(A∩B) = 15 – 12

n(A∩B) = 3

The number of students who studied both Latin and Greek is 3

Final answer:

3 of them studied both Latin and Greek.

Thus, the correct answer .3

**Ques:- If the 3 digit number AB9 is a perfect square then is A an odd digit?**

**Recent Answer**: :

A perfect square is a square number of a digit. eg 64 is a perfect number, a square of 8

Now digits AB9 is a square number of a number.

AB9 Can also be written as A multiply by B multiply by 9

Get the Square root of AB9

Assumption, A=1, B=1

1*1=1=A, 1*1=1=B Therefore,

Square root of A = A, B = B and 9=3

Therefore

An odd number is a number indivisible by 2.

for example 1,3,5,7…….

Therefore Squares A*B*9= AB9

Where a=1, b=1, 3 as digits.

Conclusion

A=1 is an odd number

**Ques:- You don't have any experience, Why I would appoint you for this post?**

**Ques:- What were some of the things about your last job that you found most difficult to do?**

**Ques:- What is your Academic Qualification**

**Ques:- What would the person who likes you least in the world say about you?**

**Ques:- Why are you leaving your job?**

**Ques:- If HEATER is written as KBDQHO, how will you encode COOLER ?**

**Recent Answer**: :

FLRIHO=cooler

**Ques:- Give me an example of your creativity.**

Recent Answer: Added by vineet kumar On 2022-08-14 16:44:48:Train speed 90 km /h

1st we have to change in m/s. then 90*5/18=25m/s

Then d=speed*time

=25*10=250m train length