Isae-supaero Interview Questions, Process, and Tips

34000

120

27 root 3

Ratio: 3/4

Answer:
11 days.

Step-by-step explanation:
In the question,

Time taken by Ramesh to finish a piece of work = 20 days

Time taken by Sushil to finish a work = 25 days

Time for which they worked together = 5 days

Sushil left after = 5 days

So,

One day work of Ramesh is,

One day work of Sushil is,

So,

Work done in 5 days is given by,

Therefore, Remaining work is given by,

Now, as the Sushil left the remaining work was done by Ramesh,

Time taken by Ramesh for the remaining work is,

Therefore, the remaining work will be completed in 11 days by Ramesh.

523

Let ‘x’ be the number of perons in the group and let ‘y’ be
amount per head which they have to pay.
Then xy = 2400.
or y = 2400/x
Since two friends have forget the purse, x-2 persons should
share the total amount(2400).
If they share, they have to make an extra contribution of
Rs 100 to pay up the bill
That is x-2 persons should pay y+100 each
or (x-2)(y+100) = 2400
or y+100 = 2400/(x-2)
or y = 2400/(x-2) – 100
Therefore we have got two equations namely,
y= 2400/x and y = 2400/(x-2) – 100
Comparing these two, we get
2400/x = 2400/(x-2) – 100
Solving this we get
x^2 – 2x -48 = 0
or (x-8) (x+6) = 0
or x = 8 or x = -6
Since ‘x’ denote the number of persons, it should be
positive.
So, x = 8.

Question is wrong i think

Answer: 450

Explanation:
10 * 150 = 1500

3 * 100 + 5 * 150 = 1050

1500 – 1050 = 450

Answer: C

Explanation:

900 — 100
100 — ? => 100/900*100 => 11.11%

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​