InDro Robotics Interview Questions, Process, and Tips

D

⇒ First part = Rs. 828

14

68 is the least number when divided by 8, 12, 18 and 24 leaves the remainders 4, 8, 14 and 20

( a ) BQDCJCMF
“TERMINAL” split it into the half we get “TERM” “INAL”

Now the first half is decreased by one and the next half is
increased by one, so we get:

“SDQLJOBM” (pls note in the ques we have “SDQIJOBM” where
‘L’ shud have come instead of ‘I’)

so “CREDIBLE” is to “BQDCJCMF”

A & B one day work= 1/18 + 1/30= 8/90

As we know that number of work is 1

1÷8/90= 1*90/8= 90/8.

Since they say “ twice the amount of work

Then ,2*90/8= 22.5 days

22

Answer is 274 .

Let the required term be x.

Pattern :- 1) Find the difference between consecutive terms as :

2 – 1 = 1

4 – 2 = 2

13 – 4 = 9

31 – 13 = 18

112 – 31 = 81

2) Now write the above numbers obtained by differences in series as :

1, 2, 9, 18, 81, y

(Suppose y be next term after 81.)

3) Look the difference series carefully and it follows the below pattern as :

(9 * 2)/1 = 18

(18 * 9)/2 = 81

(81 * 18)/9 = 162 = y (the next term after 81)

Thus the required answer is :

x = 112 + y

x = 112 +162 =274

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Lipimishra2

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Let the no. of men (originally) be x.
x no. of men require 10 days.

if however there were 10 men less it will take 10 days more for the work to be finished. ——> means x-10 men require 10+10=20 days.

10x = 20 (x-10)
x = 2x -20 => x = 20.

total distance to travel the end of the train = 360 + 140 = 500 m
speed of train 45000m/60min = 750m/min or 750m/60sec
(500m*60sec)/750m=40sec the time will take to pass

Options:
A) EDRIRL
B) DCQHQK
C) ESJFME
D) DEQJQM
Ans: A)

9 and 16