Fugro Seismic Imaging Interview Questions, Process, and Tips

43.69
Because the total distance will be =100+80000m=80100m. Thus two train coming towards, so the speed will be increase. speed will be =60+50=110km/h, The time of crossing will be 43.69 minutes.

First write equations from info:
(A) (Mon + Tue + Wed)/3 = 111 Rearrange as ——–> Tue + Wed = 111 – Mon
(B) (Tue + Wed + Thu)/3 =102 Rearrange as ——–> Tue + Wed = 102 – Thu
(C) Thu = 0.8(Mon)

Substitute equation C into B:
(B) Tue + Wed = 102 – 0.8(Mon)

At this point I changed the values for clearer algebra:
Mon = x
Tue + Wed = y

Re-write equations A & B with new values:
(A) y = 111 – x
(B) y = 102 – 0.8x

Solve simultaneous equations:

111 – x = 102 – 0.8x
111 – 102 = x – 0.8x (Re-arraged)
9 = 0.2x
x = 45

Thus, Mon = 45C

Thu = 0.8(45)
Thu = 36C

So the answer is it was 36C on Thursday

let x=speed
t=time taken when speed is x so…
xt=4/5x(t+40)
t=160 minutes
2 hr 40 minutes

EMNXDS

it is based on the right shift operation on the perticular digit

xy+2y-x=6
xy+2y-x-2=6-2
y(x+2)-1(x+2)=4
(y-1)(x+2)=4
so c is 4

12

Karnataka

democrate=1008

(115+65+x)/3=95
x=105

Ramji sir

0,8x= y
y – 0,7y = 270

y= 270 / 0,3
y=900

0,8x=900
x=1125

I will first need to understand why he/she behaves so to establish the exact cause and try persuade him to appreciate roles and responsibilities of the various Team members in trying to achieve organizational goals.

Given y/x = 1/3, x+2y =10
3y=x
Then substitute x=3y in x+2y=10

3y+2y=10
5y=10
y=2

Then substitute y=2 in x=3y
x=3*2
x=6
: x=6, y=2

a

None of these