Envecon Interview Questions, Process, and Tips

1/4E(E decreses by 4 times)

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46

60 liter

let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer

9999991 (6k+_1) form

126
cos if one of the factor is given for hcf and lcm and multiply hcf and lcm and them divide it by the given factor
so 18*3780/540=18*7=126

20
speed of downstream=speed at still water+flow
= 15+5=20

c=a/b
c=a-1
=>b=a/c
=>b=a/a-1

4:3
A—–>B (first train)
B——>A(second train)
A/B=Srureroot((time to B)/(time to A))