Drizly Interview Questions, Process, and Tips

=36*84/ lcm
= 36 * 84 / (12 * 3 * 7 )
HCF= 12

A’s speed=6 mph ,B’s speed=8 mph
Let, after x hrs, they will meet.
so, the distance traveled by A in x hrs should be the same as the distance traveled by B in (x-1/2)hrs [as B started the journey after 30 min of A]
Thus, 6x=8(x-1/2)[as distance=speed*time]
=>8x-6x=4
=>2x=4
=>x=2
after 2 hrs they will meet so time=(9+2)=11.00 a.m

d

1
6=1x2x3
24=2x3x4
60=3x4x5
120=4x5x6
210=5x6x7
336=6x7x8

Its Alphabet “e”

(x-2)^3==x^3-6x^2+12x-8
(x-2)^3==(2^(2/3)+2^(1/3))^3
therefore,by solving
Ans: x^3-6x^2+x== -8-5*2^(2/3)-5*2^(1/3)

6561 → 6560/2 [-1]
3280
1640
820
410
205 [+1] =206
103 → [-1] = 102
51 [+1] = 52
26
13 [-1] = 12
6
3 [+1] 4
2
1

speed=mile/hour
.•. time taken to travel M miles is

So, time =distance/speed
=M/m/h
=Mh/m hrs

8

decrease two times

40