Ques:- When x is real what is the least value of (x**2-6*x+5)/(x**2+2*x+1)
Recent Answer : Added by Admin On 2020-05-17 12:01:23:
(x**2 – 6* x + 5) = (x-1)*(x-5)
(x**2 + 2 * x + 1) = (x + 1) * (x+1) = (x+1)**2
For what x is (x-1)*(x-5)/( (x+1)**2) a minimum?
One way to answer this question is by using calculus.
Take the derivative, and set to zero.
Since this is a fraction of polynomials, and a fraction is
zero only if it’s numerator is zero, we need calculate only
the numerator of the derivative and set it to zero.
The numerator of the
Derivative of (x-1)*(x-5)/( (x+1)**2) is
( (x-1) + (x-5) ) ( x+1)**2 – (x-1)(x-5)( 2 (x+1) )
= (2 x – 6) (x+1)**2 – (2) (x-1)(x-5) (x+1)
= 0
Divide through by 2 (x+1)
(x-3)(x+1) – (x-1)(x-5) = 0
(x**2 – 2 x – 3 ) – (x**2 – 6 x + 5) = 0
x**2 – x**2 – 2 x + 6 x – 3 – 5 = 0
4 x – 8 = 0
x = 2
Plugging in x = 2 into the original
(x**2-6*x+5)/(x**2+2*x+1)
gives us (2**2 – 6 * 2 + 5)/(2**2 + 2*2 + 1)
= (4 – 12 + 5) / (4 + 4 + 1) = -3/9 = -1/3
Least value is -1/3
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Ques:- 1.14 expressed as a percent of 1.9 is
A. 6%
B. 10%
C. 60%
D. 90%
Recent Answer : Added by Varshitha On 2022-06-20 11:28:59:
.
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Ques:- what will be reminder after (16)^15 is devided by the 254…
A. 2
B. 0
C. 1
D. 128
Recent Answer : Added by Damodharan M On 2023-05-22 03:48:14:
I need a answers from hakuna matata questions
Ques:- x==2+2^(2/3)+2^(1/3) .Then what is the value of x^3-6X^2+x ? here X^Y indicates X to the power of Y.
Recent Answer : Added by Admin On 2020-05-17 12:04:34:
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Ques:- xy-x+2y = 6 equation is shifted to form equation xy=c what is c?
Recent Answer : Added by Admin On 2020-05-17 12:01:13:
xy+2y-x=6
xy+2y-x-2=6-2
y(x+2)-1(x+2)=4
(y-1)(x+2)=4
so c is 4
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Recent Answer : Added by Elcin Kumar M On 2022-05-17 08:55:19:
I would design a voice integrated clock that reads out the time aloud whenever people ask for time
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Ques:- The price for a pair of cuff links is Rs.1.00. The price for a 5 pair package of cuff links is Rs.3.40. The 5 pair package is what percent cheaper per paid than 5 pairs purchased separately?
A. 30%
B. 32%
C. 47%
D. 62%
Recent Answer : Added by Admin On 2022-09-25 04:09:54:
B. 32%
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Ques:- Navin walked 20 metres towards the East took a left turn and walked 10 metres and again took a left turn and walked 20metres. How far is he from his starting position?
A. 10 metres
B. 50 metres
C. 40 metres
D. 30 metres
E. None of these
Recent Answer : Added by Admin On 2020-05-17 12:03:42:
( a ) 10 metres
Ques:- 7^101+18^101 is a multiple of a.15 b.25 c.35 d.45
Recent Answer : Added by Khagesh On 2022-10-17 15:58:03:
25
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Ques:- A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is:
Recent Answer : Added by Admin On 2022-09-28 18:02:37:
Let the age of the man be x
Then age of his son becomes (x−24)
2 years later from now,
Age of man will be = x+2
and age of his son will be =(x−24+2)=x−22
According to question,
2(x−22)=x+2
i.e., 2x−44=x+2
i.e., x=46
Therefore ,
Present age of man=46 years
And present age of his son =46−24=22 years
Ques:- Sachin is younger than Rahul by 4 years. If their ages are in the respective ratio of 7:9, how old is Sachin?
Recent Answer : Added by Davide On 2021-08-10 09:39:24:
Sachin is 14 years old whereas Rahu is 18 years old.
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Recent Answer : Added by Naga Harish On 2022-03-13 16:35:29:
21
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Ques:- The equal amounts of money are deposited in two banks each at 15% per annum for 3.5 years and 5 years respectively. If the difference between their interests is Rs.144, find the each sum?
Ques:- a train is moving at speed of 25 kmph , another train moving the same direction at a speed of 49 kmph crossed a man in the first train in 10 sec ? wht is the length of the second train ?
Recent Answer : Added by Admin On 2020-05-17 12:04:15:
Relative velocity of trains = 49kmph -25 kmph = 24kmph
=6.67m/s
Time taken to cross the first train = 10 sec
Length of the second train = Relative Velocity * Time taken
to cross the first Train = 6.67 *10 = 66.7 metres
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(x**2 – 6* x + 5) = (x-1)*(x-5)
(x**2 + 2 * x + 1) = (x + 1) * (x+1) = (x+1)**2
For what x is (x-1)*(x-5)/( (x+1)**2) a minimum?
One way to answer this question is by using calculus.
Take the derivative, and set to zero.
Since this is a fraction of polynomials, and a fraction is
zero only if it’s numerator is zero, we need calculate only
the numerator of the derivative and set it to zero.
The numerator of the
Derivative of (x-1)*(x-5)/( (x+1)**2) is
( (x-1) + (x-5) ) ( x+1)**2 – (x-1)(x-5)( 2 (x+1) )
= (2 x – 6) (x+1)**2 – (2) (x-1)(x-5) (x+1)
= 0
Divide through by 2 (x+1)
(x-3)(x+1) – (x-1)(x-5) = 0
(x**2 – 2 x – 3 ) – (x**2 – 6 x + 5) = 0
x**2 – x**2 – 2 x + 6 x – 3 – 5 = 0
4 x – 8 = 0
x = 2
Plugging in x = 2 into the original
(x**2-6*x+5)/(x**2+2*x+1)
gives us (2**2 – 6 * 2 + 5)/(2**2 + 2*2 + 1)
= (4 – 12 + 5) / (4 + 4 + 1) = -3/9 = -1/3
Least value is -1/3