ATAS Interview Questions, Process, and Tips

50

47.5

C

E

0.000256

3 hours ago.

Thin candle melts 3/4 in 3 hours leaving 1/4
Where as in the same time thick candle melts 3/6 leaving 3/6 which is 1/2. Now thick candle is exactly twice than the thin candle.

Or via modeling:

We need to find time at which the length of the thin candle is half the thick candle. Let x be the time. Thin candle melts at 1/4 an hour and thick candle melts at 1/6 an hour. In x hours they melt at x/4 and x/6 respectively. What’s left will be 1 – x/4 and 1 – x/6. We need to find x at which :

2 * (1 – (x/4)) = 1 – (x/6)

This equation results in x = 3

I think speed of printing per minute has nothing do to with how long printer being at work.

If “given day” = 8 hours.
8h = 480m

x = 176400 / 480 = 367.5 lines per minute.

7 : 3

as i assume the time taken to complete the job is not to be
changed while increasing the employees as it does not
clearly states so……….
30 men wrk for 9 hrs
therefore for the work to be done if no of workers is
increases the no of hrs / day to work should decrease so
here s a inverse relation
solving further we get
30 = K /9 ==> K= 270
now
40 = 270/y ==> y= 6.75
therefore ans is d)none

1896172

252

Answer is 16
1,2,4,7,11,….
1+(1) =2
2+(2) =4
4+(3) =7
7+(4) =11
Therefore
11+(5) =16

B. No such pair exists

Let’s say,

I have x coins of 50 paise and (80-x) coins of 100 paise,so the equation is like this ,
50x + (80-x)*100 = 64*100
x = 32
So ,I have 32 coins of 50 paise

red

exactly