Asmitagroup-umrao hospital Interview Questions, Process, and Tips

3630

C. 22%

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

132

Cut it horizontally so both can have equal share and same in shape.

23

31

( A ) 124

c

I believe it will be 30 km/hr

Options:
A) EDRIRL
B) DCQHQK
C) ESJFME
D) DEQJQM
Ans: A)

Let and A and B are playing and A has 3$ and B won 3 times.

Total money earn by A = no of games A won – no of games A loss
if A loss game means B won.
Therefore
Total money earn by A = no of games A won – no of games B won
3 = no of games A won -3
no of games A won=6
So
A won = 6 games
B won = 3 games

Hence total no of games is 9

Its Alphabet “e”

2nd

8+3+4=15
15+(7)=22
22 is divisible by 11.
So,7 is right answer. Option C

Answer is 274 .

Let the required term be x.

Pattern :- 1) Find the difference between consecutive terms as :

2 – 1 = 1

4 – 2 = 2

13 – 4 = 9

31 – 13 = 18

112 – 31 = 81

2) Now write the above numbers obtained by differences in series as :

1, 2, 9, 18, 81, y

(Suppose y be next term after 81.)

3) Look the difference series carefully and it follows the below pattern as :

(9 * 2)/1 = 18

(18 * 9)/2 = 81

(81 * 18)/9 = 162 = y (the next term after 81)

Thus the required answer is :

x = 112 + y

x = 112 +162 =274