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We are given:
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January 7, 1992 was a Tuesday
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We need to find the day of the week on January 7, 1997 — exactly 5 years later
🧮 Step 1: Count the number of leap years and normal years from 1992 to 1997
From Jan 7, 1992 to Jan 7, 1997 = 5 years
Years: 1992, 1993, 1994, 1995, 1996
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Leap years in this range: 1992 and 1996 ⇒ 2 leap years (each adds 2 odd days)
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Ordinary years: 1993, 1994, 1995 ⇒ 3 years (each adds 1 odd day)
🧮 Total odd days = (2 × 2) + (3 × 1) = 4 + 3 = 7 odd days
→ 7 odd days = exactly 1 week
So the day of the week remains the same
✅ Final Answer:
January 7, 1997 was also a Tuesday.
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