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Length of the train = 100 meters
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Length of the platform = 100 meters
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Total distance to be covered = 100 m (train) + 100 m (platform) = 200 meters
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Time taken = Not given directly (you wrote “in seconds”), so we assume you want to find time if speed is given — or vice versa.
But you asked: “The speed of the train is?” — so we must be missing the time.
Let’s assume you meant to ask:
❓ If a 100-meter-long train passes a 100-meter-long platform in 10 seconds, what is the speed of the train?
✅ Step 1: Total distance = 100 + 100 = 200 meters
✅ Step 2: Time = 10 seconds
✅ Step 3: Speed = Distance ÷ Time = 200 ÷ 10 = 20 m/s
✅ Step 4: Convert to km/h → 20 × 3.6 = 72 km/h
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✅ Final Answer (if time = 10 seconds): Speed of the train = 72 km/h
If you have a different time value, please provide it and I’ll recalculate accordingly.
In any given month, the 29th day occurs as long as the month has at least 29 days. Since every month of the year has at least 29 days, the 29th day appears in every month.
So, over a span of 400 years:
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Each year has 12 months
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So, 400 × 12 = 4,800 months
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That means the 29th day appears 4,800 times over 400 years.
However, if you’re asking about how many times February 29 specifically occurs in 400 years — that’s a bit different, because February 29 only comes in leap years.
Let’s calculate:
🔹 Leap year rules:
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A year is a leap year if it’s divisible by 4
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Except if it’s divisible by 100 — unless it’s also divisible by 400
So, in 400 years:
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Total years divisible by 4 = 100
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Out of those, 3 century years (1700, 1800, 1900) are not leap years
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But 2000 is a leap year (divisible by 400)
➡️ Final count: 100 – 3 + 1 = 98 leap years
That means:
🟢 February 29 appears 97 times in 400 years.
✔ Final Answer:
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The 29th day of the month occurs 4,800 times in 400 years
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February 29 (leap day) occurs 97 times in 400 years
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