Akal information systems ltd. Interview Questions, Process, and Tips

A

Turn on a switch and leave it for some ten minutes. Turn it off, turn a second one on and open the door and go into the room. The glowing bulb corresponds to second switch. The bulb that is hot corresponds to first switch, as it was turned on for ten minutes and have heated up. The cold and not-glowing bulb corresponds to the third switch

Ans is 2(Prime numbers)

Sum of 5 consecutive nos is 35

so X + (X+1) + (X+2) + (X+3)+ (X+4) = 35

5X + 10 = 35

X = 5

So the 5 consecutive numbers are : 5, 6, 7, 8, 9

The Prime numbers are 5 and 7

Previous their age was 21 and 18 respectively
Presently, after 6 years the age is 27 and 24.

40

Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74

ANS = 74

x+8y=20, x=-3y
(-3y)+8y=20
5y=20
y=4
The answer for y is 4

73.
one year back father = 72 and son = 36.

Initially, potatoes have 99% water by weight ; which means they have 1% solid non-water content.

1% of 100 kg = 1 kg

Now even when they dehydrate,this 1kg solid mass remains constant.

It is given that finally, 98% is water by weight , which implies that 2% is non-water solid.

This means 2% of total weight = 1 kg

Total weight *2/100 = 1 kg

Therefore, total weight finally = 50 kg.

125

To determine how many consecutive zeros the product of S will end with, we need to find the highest power of 10 that divides the product. This is equivalent to finding the highest power of 5 that divides the product, since the number of factors of 2 will always be greater than the number of factors of 5.

The primes in S are {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}.

There are 24 primes in S, so the product of S is:

2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 x 37 x 41 x 43 x 47 x 53 x 59 x 61 x 67 x 71 x 73 x 79 x 83 x 89 x 97

We need to find the highest power of 5 that divides this product. To do this, we count the number of factors of 5 in the prime factorization of each number in S.

5 appears once: 5
5 appears once: 25
5 appears once: 35
5 appears once: 55
5 appears once: 65
5 appears once: 85
So, there are six factors of 5 in the product of S. However, we also need to consider the powers of 5 that arise from the factors 25, 35, 55, and 65.

25 = 5 x 5 appears once: 25
35 = 5 x 7 appears once: 35
55 = 5 x 11 appears once: 55
65 = 5 x 13 appears once: 65
Each of these numbers contributes an additional factor of 5 to the product of S. Therefore, there are 6 + 4 = 10 factors of 5 in the product of S.

Since each factor of 5 corresponds to a factor of 10, we know that the product of S will end with 10 zeros. Therefore, the product of S will end with 10 consecutive zeros

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