Abu dhabi vocational education and training institute (adveti) Interview Questions, Process, and Tips

C

MEDICINE will become EOJDJEFM in the same code.

Joe is fencing in a square area of 576 square feet.
Fence posts, which are needed every three feet, cost 32.00 each.
The fencing cost 4.50 per foot. What is the total cost of the fencing materials?

Solution:-
Area of Square is 576 sq ft.
so, the length of side = root(576) = 24 ft

Since the fencing would be done on the perimeter, we would need that
formula is 4*side = 96 ft.

Number of Fence post needed = 96/3 = 32

1 Fence post cost = 32
32 Fence Post cost = 32 * 32 = 1024

Fencing cost = Perimeter * fencing cost = 96 * 4.5 = 432

Total Cost = 432 + 1024 = 1456

The answer is A)

y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg

y2 – y1 = 10 Rs/kg

The distance between the y and y1 is

y – y1 = 64.5 – 62 = 2.5

x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75

The target price is calculated by the lever method.

x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5

The ratio is of y1 to y2 is

0.75 : 0.25

Divide by both by 0.25

3 : 1

Ratio is 3:2:1

Total=6

Reverse of ratio is 1/3:1/2:1/1

Portion of first part is=1/3*6=>2

Portion of second part is=1/2*6=>3

Portion of third part is 1*6=>6

∴So the new ratio is 2:3:6

28
to arrange m objects in n places => nCm
i.e. for this example m=2(+,- sign) and n = 8(places between two number from 1 to 9)
SO, answer is : 8C2 = (8*7) / 2 = 28

maternal grand mother

mother

Prosperity for all

(3/4)*(L/Sp)=30
L/Sq=75
(3/4)*(Sq/Sp)=30/75
Sq/Sp=8/15
Sp/Sq=15/8

120

c

126
cos if one of the factor is given for hcf and lcm and multiply hcf and lcm and them divide it by the given factor
so 18*3780/540=18*7=126

T=Distance/speed
T=(150+200)/(120×5/18)

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