72 kmph

Since the total train length passed the tunnel so the distance would be the length of train added to the tunnel legth
D=150+300=450 mt.
speed = distance/time
speed = 450/(40.5/3600)
speed =40,000 mt/sec

Relative speed =65-45km/hr
Relative speed=20km/hr
Convert to m/s
S=20*5/18
S=5.555
Length of the faster train =5.55555*18seconds
=100meters

45 km/hr

79.2

1(1/7)hr

240-24
650-?
?=24*650/240
65SEC

The Answer is c

3600 sec in 1 hr.. 1000 M in 1 km so to covert m/s to km /hr you multiply the value with (3000/1000) .. so 3000 divided by 1000 will give you 18/5 it’s like constant value.. to convert m/s to km/ hr we can use this 18/5.. hope you understand

let convert meter to kilometer by multiply 18/5 then answer be 14*(18/5)=50.4 km/s

1km = 1000m
Xkm = 300m
X=0.30km

1hr = 3,600s
X = 40.5s
0.01125hr
Therefore; 0.3km/0.1125hr= 26.6666=26.67km/hr

Train speed 90 km /h
1st we have to change in m/s. then 90*5/18=25m/s
Then d=speed*time
=25*10=250m train length

Friday

30 Sec

35 is not the factor of 120 so…35 is the answer

= 100 + 100 = 200 m

Time taken by train = 10 sec.

∵ Speed = Distance/Time

⇒ Speed of train = 200/10 = 20 m/sec.

∴ Speed of train = 20 × 18/5 = 72 kmph.

In question they left 10 seconds

B

4:3
A—–>B (first train)
B——>A(second train)
A/B=Srureroot((time to B)/(time to A))

required number =H.C.F of (73-25),(97-73) & (97-25)
=H.C.F of 48 , 24 and 72 = 4 (c)

31
cos
434-403=31
465-434=31

d

d
HCF= 2
LCM = 2*5*7 = 70

126
cos if one of the factor is given for hcf and lcm and multiply hcf and lcm and them divide it by the given factor
so 18*3780/540=18*7=126

20 litres
cos
140 280 320 liters oil are exactly fittable in 20 litred tin

27

12*336/84=48

270/(27*1000)*3600=36

60*5/18*9=150

DISTANCE=TIME *SPEED
D=?
48*(5/18)=13.33m/s
D=9*13.333=120m

17 secs