Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
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A. Rs. 105000
B. Rs. 111500
C. Rs. 130000
D. Rs. 170000
Recent Answer : :
117000
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A. 16
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C. 48
D. 96
Recent Answer : :
c
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1/24S
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B. 20 sec
C. 25 sec
D. 30 sec
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30 Sec
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Ques:- The ratio fo Boys to Girls is 6:4. 60% of the boys and 40% of girls take lunch in the canteen. What % of class takes lunch in canteen.
Recent Answer : :
assume the ratio 6:4 to be 60:40
boys taking lunch in canteen=60% of 60=36
Girls taking lunch in the canteen=40% of 40=16
Total boys and girls taking lunch in the canteen=52
Total students we assumed is 60+40=100
Therefore percentage of boys and girls taking lunch in the canteen=(52/100)*100=52%
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A. Christian Dior
B. Coco Chanel
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D. Hubert de Givenchy
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So answer will be 1 and all other answers are wrong. You can
run your equation in C code and check the output.
Ques:- In a certain company 20% of the men and 40% of the women attended the annual company picnic. If 35% of all the employees are men .What % of all the employee went to the picnic?
Recent Answer : :
Suppose that total 100 employees are in company….. out of that 35 are man and remaining 65 are women.
20% of man 35 = 20*35/100
40% of women = 40*65/100
total employees = 7+26 = 33 out of 100
so, Ans = 33 %
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North-east
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Ques:- Each side of a rectangle is increased by 100% . How much the percentage of area will be increased
Recent Answer : :
x,y sides of rectangle
area=xy
increased by 100% =double length
hence
new area=4xy
increased area=4xy-xy=3xy
percentage of area will be increased
by 300%
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.