🟩 Future Plans:
I aim to gain industry experience, improve my skills, and take on leadership roles in the next few years. My long-term goal is to contribute to meaningful projects and grow into a managerial position.
🧠 Personal SWOT Analysis:
✔️ Strengths: Fast learner, team player, punctual
❌ Weakness: Overthinking, public speaking nerves
📈 Opportunity: Growing field, access to online learning
⚠️ Threat: Fast-changing tech, job competition
🏆 Achievements:
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Completed certification in [Your Skill/Tool]
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Led a successful [project/event/internship]
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Recognized as a top performer during training/internship
Let me know if you’d like this tailored to a specific job or field.
I understand that I may not tick every technical box, but I bring strong problem-solving skills, a quick learning ability, and a genuine willingness to grow. I’ve handled challenging tasks before by adapting fast, collaborating well, and staying committed to results. I believe attitude, communication, and consistency often make a bigger impact than just technical expertise—and I’m ready to prove that with real outcomes if given the opportunity.
To find the greatest 4-digit number which is exactly divisible by 12, 18, 21, and 28, follow these steps:
🟠 Step 1: Find the Least Common Multiple (LCM) of the numbers
We need the LCM of: 12, 18, 21, and 28
First, find their prime factorizations:
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12 = 2² × 3
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18 = 2 × 3²
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21 = 3 × 7
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28 = 2² × 7
Now take the highest powers of all prime numbers that appear:
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2² (from 12 or 28)
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3² (from 18)
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7 (from 21 or 28)
LCM = 2² × 3² × 7 = 4 × 9 × 7 = 252
🟠 Step 2: Find the greatest 4-digit number divisible by 252
The largest 4-digit number is 9999
Divide 9999 by 252:
9999 ÷ 252 ≈ 39.682
So, take the whole number part → 39
Now multiply: 252 × 39 = 9828
✅ Final Answer:
The greatest 4-digit number exactly divisible by 12, 18, 21, and 28 is:
👉 9828