Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Ques:- Every day a cyclist meets a train at a particular crossing .The road is straight before the crossing and both are travelling in the same direction.Cyclist travels with a speed of 10 kmph.One day the cyclist come late by 25 minutes and meets the train 5 km before the crossing.What is the speed of the train?
Ques:- The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
Recent Answer :
: 31
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Recent Answer :
: 4500 sal of jan
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Recent Answer :
: ans: A/2
u get a diamond shape when u join those mid points
consider the 4 unshaded triangles
and u can form 2 square
when u analyse the squares u will get the answer
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Ques:- The LCM of three different numbers is 120. Which of the following cannot be their HCF?
A. 8
B. 12
C. 24
D. 35
Recent Answer :
: 35 is not the factor of 120 so…35 is the answer
Ques:- A train takes 9 sec to cross a pole. If the speed of the train is 48 kmph, then length of the train is
A. 80 m
B. 90 m
C. 120 m
D. 150 m
Recent Answer :
: DISTANCE=TIME *SPEED
D=?
48*(5/18)=13.33m/s
D=9*13.333=120m
Ques:- A clerk multiplied a number by ten when it should have been divided by ten.The ans he got was 100.what should the ans have been?
Recent Answer :
: Let the number be X,
Instead of dividing the number by 10, i.e.,X*10.
he got the result as 100,
so, (X*10)=100
X=100/10
X=10.
BUt he has to divide X by 10,
so, X/10=10/10=1.
obviously the answer is 1.
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Recent Answer :
: just will draw the line first and then draw three concentric circles
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the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;