Trocaire college Interview Questions, Process, and Tips

Ans. 175
Relative speed in m/s=40-22=18X5/18=5m/s
Total distance=125+x m
T=1min=60 s
D=sXt
125+x=5X60
x=175

C. 96

answer
R-R*d/100-5(1-d/100)

answer is one

Article price=200
After 25%increase =250
After 25% decrease =187.5

B. 3 : 2

20

150m

original cost is 100^2 / (100^2 – p^2) Rs

1 through 24, divisible by 2 in descending order.

That leaves you with:
24, 22, 20, 18, 16, 14, 12, 10, 8, 6, 4, 2

8th place FROM the bottom means your answer will be 16.

First write equations from info:
(A) (Mon + Tue + Wed)/3 = 111 Rearrange as ——–> Tue + Wed = 111 – Mon
(B) (Tue + Wed + Thu)/3 =102 Rearrange as ——–> Tue + Wed = 102 – Thu
(C) Thu = 0.8(Mon)

Substitute equation C into B:
(B) Tue + Wed = 102 – 0.8(Mon)

At this point I changed the values for clearer algebra:
Mon = x
Tue + Wed = y

Re-write equations A & B with new values:
(A) y = 111 – x
(B) y = 102 – 0.8x

Solve simultaneous equations:

111 – x = 102 – 0.8x
111 – 102 = x – 0.8x (Re-arraged)
9 = 0.2x
x = 45

Thus, Mon = 45C

Thu = 0.8(45)
Thu = 36C

So the answer is it was 36C on Thursday

8

Days taken by A to complete whole work= 140 days
Days taken by B to complete whole work= 105 days

A’s 1 day work= 1/140
B’s 1 day work= 1/105
On adding these together we get: 1/60 (1 day work by working together)

So, together they will be able to complete it in 60 days

A. Tuesday

47.5