x:y=18:11
40 km avrege speed
speed = distence / time
60km/hr=distance / 9 sec
km / hr to m / s==> 60*1000 / 1* 3600 = 16.667
16.667*9 = distance
150 m is the answer
C. Monday
A year has 52 weeks and every week has 7 days.
We just add up one day to the present day of the year and that would automatically act as the day of the next year.
In case of leap years in between, one extra day gets added in the entire year making it 366 days instead of 365 days in an ordinary year and we add two days in that case.
Options:
A) EDRIRL
B) DCQHQK
C) ESJFME
D) DEQJQM
Ans: A)
36,20
answer is 100
[(45 men*8hours)/30 meters]=12 (working rate)
[(x men*5 hours)/50 meters]=12 (working rate is same)
then x=100
Out of 10 persons, 4 are graduates; so, (10 – 4) = 6 are under-graduates.
If there is no restriction, any three can be chosen from the ten in (10C3) = 120 ways.
Now, if all three chosen are under-graduates; it can take place in (6C3) = 20 ways.
Therefore, the probability that there will be no graduate among the three chosen = (20 / 120) = (1 / 6).
Therefore, the probability that there will be at least one graduate among the three chosen = {1 – (1 / 6)} = (5 / 6) = 0.8333.
40
Answer is 274 .
Let the required term be x.
Pattern :- 1) Find the difference between consecutive terms as :
2 – 1 = 1
4 – 2 = 2
13 – 4 = 9
31 – 13 = 18
112 – 31 = 81
2) Now write the above numbers obtained by differences in series as :
1, 2, 9, 18, 81, y
(Suppose y be next term after 81.)
3) Look the difference series carefully and it follows the below pattern as :
(9 * 2)/1 = 18
(18 * 9)/2 = 81
(81 * 18)/9 = 162 = y (the next term after 81)
Thus the required answer is :
x = 112 + y
x = 112 +162 =274
( a ) BQDCJCMF
“TERMINAL” split it into the half we get “TERM” “INAL”
Now the first half is decreased by one and the next half is
increased by one, so we get:
“SDQLJOBM” (pls note in the ques we have “SDQIJOBM” where
‘L’ shud have come instead of ‘I’)
so “CREDIBLE” is to “BQDCJCMF”
Answer is 8,12,5,20
8+2=10
12-2=10
5*2=10
20/10=10