Triumvirate environmental Interview Questions, Process, and Tips

C. 39

3*2+1 = 7
15*2+1 = *31*
31*2+1 = 63
63*2+1 = 127
127*2+1 = 255
255*2+1 = 511

d=7s—–equation 1
d=5(s+12)
7s=5(s+12)
7s=5s+60
2s=60
s=30
from equation 1
d=7*30
d =210km

its a tricky question and very funny too.
the answer is 45% only which is gained by the minute hand.

360 years old
Nepo’s son age = x
Nepo’s age = 3x
Nepo’s father age = 2*3x + 40

x + 3x + 6x + 40 = 1240
10x = 1200
x = 120

Nepos age = 3* 120 = 360 years

divide 100 by 7, and you get 14.28. (Obviously you aren’t talking about decimals here) and so 14 numbers can be divisible by 7 up to 100.

The answer is 14.

42m

no

A. Tea

The greatest number that will divide 187, 233 and 279 leaving the same remainder in each case.

To find : The number ?

Solution :

First we find the difference between these numbers.

The required numbers are

233-187=46

279-233=46

279-187=92

Now, We find the HCF of 46 and 92.

Therefore, The required largest number is 46.

75/8 days

Sum of all numbers in series= 870 (I.e 312+162+132+142+122)
Average=sum of numbers/count of numbers
Average= 870/5
= 174

pass English =80%
fail=100-80=20%
pass Math = 70%
fail in Math=100-70=30%
fail in both=10%
total fail students= fail in Eng+fail in Math-common
= 20+30-10=40%
if 40% fail then 60% will pass
let total students=x
hence
60% 0f (total students)=144
60/100 of (x)= 144
x=(144×100)/60
X=240
total students=240

224