Chetham's school of music Interview Questions, Process, and Tips

1) time =20mins,speed=15kmph=15*(5/18)=25/6 m/sec
distance=20*(25/6)=250/3 m
then 2) given as time =15min
speed=250/3*15=(50/9)*(18/5)kmph=20kmph

2x+x+2x+x = 300m
6x = 300
x = 300/6 = 50m
50m x 100m = 5,000 m2

No loss no gain.

Now as per question, Kamal invested for 12 months and Sameer invested for 7 months.
So, Kamal:Sameer=(9000×12​):(8000×7​)
=108.56=27:14
Sameer ratio in profit will be =6970×4114​=Rs.2380

the answer is 3:10
explanation:

let the first number be x
and the second number be y
(7/8)((3/7)x)=(25/100)((45/100)y) given
ie.., 21x/56= 9y/80
on solving we get x:y= 3:10
is the answer

sorry the above ans was typed by mistake the correct ans is…..
1027.05 ? 314.005 + 112.25 = ?
ans:
1027.05 – 314.005 + 112.25 = 825.295

Answer:

Since the car has met the person 20 minutes before hand, it has actually saved 10 mins of journey (to and fro)

since the man has started 1.30 hrs before and car has met him 10 mins before actual time he takes to reach daily is 1hr and 20 mins

At 680Km

75 degrees
30h – 11/2 m = 240 – 165 = 75 ..

x:y=18:11

31yrs

Given:

In a group of 15 students,

7 have studied Latin,

8 have studied Greek,

3 have not studied either.

To find:

The number of students who studied both Latin and Greek.

Solution:

In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.

Therefore,

n(A∪B) = 15 – 3

n(A∪B) = 12

7 have studied Latin,

n(A) = 7

8 have studied Greek,

n(B) = 8

n(A∩B) is the number of students who studied both Latin and Greek.

n(A∩B) = n(A) + n(B) – n(A∪B)

n(A∩B) = 7 + 8 – 12

n(A∩B) = 15 – 12

n(A∩B) = 3

The number of students who studied both Latin and Greek is 3

Final answer:

3 of them studied both Latin and Greek.

Thus, the correct answer .3