Transfera transport&logistics Interview Questions, Process, and Tips

Avg = 2(X*Y)/X+Y
2*(60*40)/60+40
2*(2400)/100
2*24
48.

11 14
12 15
13 16
=======
14 17
the answers is 14

25

Given:
Speed of man downstream= 30/3=10km/h
Speed of man in upstream=18/3=6km/h
Speed of man in still water=1/2 (speed of upstream+ speed of down stream)
= 1/2 (10+6)
=1/2*16
=8km/h

ans: none
let it may be any number the square cant end in 8

12

( c ) R or T

Answer is 274 .

Let the required term be x.

Pattern :- 1) Find the difference between consecutive terms as :

2 – 1 = 1

4 – 2 = 2

13 – 4 = 9

31 – 13 = 18

112 – 31 = 81

2) Now write the above numbers obtained by differences in series as :

1, 2, 9, 18, 81, y

(Suppose y be next term after 81.)

3) Look the difference series carefully and it follows the below pattern as :

(9 * 2)/1 = 18

(18 * 9)/2 = 81

(81 * 18)/9 = 162 = y (the next term after 81)

Thus the required answer is :

x = 112 + y

x = 112 +162 =274

Suppose that x glassses are supplied safely , therefore
(100-x) glases are damage. Then equation is :
3x – 3(100-x) = 270
on solving this equation value of x comes out to be 95.

28

the answer is E

3500*10/100

3500*11.5/100 = 402.5 per year
402.5×3 = R1207.5

1 ball – 4 runs (1st batter – 94+4=98)
2 ball – 3 runs and one run is short run during running between the wicket (1st batter- 98+3-1 =100)and strike changes for 2nd batter
3 ball – 6 runs ( 2nd batter 94+6=100)

10%=394;50%=1970;250%=9850;30%=1182;
250%+30%=9850+1182=11032